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Jef123

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^{2}> n+1 for all n≥2

2. First, (2)^2>2+1...4>3

Now for the induction step, (n+1)

^{2}> 2n+2

Can I just show that n

^{2}+2n+1 > 2n+1+1 because 2n+1 = 2n+1 for both sides and n

^{2}>1 for all n>1

I'm pretty sure what I did is not acceptable fro this to be considered proved