Is it Possible for x^2 to Exceed 900?

[PeroK]

Ok. Great. And the fact that $(-2)^{2*1/2}= -2$ is true but we ignore it and say $(-2)^{2*1/2}= |-2|=2$. Yes?

Keep things simple:
$$(x^2)^{1/2} = \sqrt{x^2} = |x|$$$$x^{(2*\frac 1 2)} = x$$

 

[mark2142]

It doesn't really have anything to do with y=x2.

I meant to substitute $x^2$ with $y$ so to make it more clear. Square root of y is defined to be positive root. My explanation seems right.
I am not saying I don’t agree with yours. It’s just I get mine and it’s easy to remember.

 

[mark2142]

Thank you.