¿Is it possible the decay of rho neutral meson to two pions? 1. The problem statement, all variables and given/known data We initially have the neutral rho meson -----> pion+ + pion- ¿Is this reaction possible? ¿What are the conserved quantities?¿Which is the interaction involved in the process? 2. Relevant equations Conservation laws of energy, momentum, angular momentum, electric charge, C-parity, parity,Isospin, cp symmetry. Here we have the properties of the involved particles: http://en.wikipedia.org/wiki/Rho_meson http://en.wikipedia.org/wiki/Pion 3. The attempt at a solution Well i am using the book of yung kuo "Problems and solutions in atomic, nuclear and particle physics", it is the 3018 problem. The book says that the decay is possible, by strong interaction, and that means that every symmetry is conserved, there isn't any violation. The problem is the next: -for the angular momentum i have found that for the rho meson is 1, and for the pions + and - is 0. So we have 1---->0 + 0, the composition of angular momentum says that in the second part of the equality is not possible to find J=1, so I think that conservation of angular momentun is violated ¿what am I doing wrong?. -for the parity we have (-1 of the rho) -----> (-1 of the pion+ and -1 of the pion-) So multipliying we have -1 = 1 so it is violated, I think that perhaps the mistake is that the parity of the pion- is oppossite to the parity of his antiparticle(pion+), but it is not listed on the table of the wikipedia ¿is this the mistake?. ¿The parity of an antiparticle is the same as the one of the original particle? . -for the C-parity we have that the rho meson has a -1, but for the pions is not defined ¿is it violated?.