Is It Possible to Have an Imaginary Normalisation Constant?

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SUMMARY

The discussion centers on the normalization constant C for a one-dimensional quantum system represented by the wavefunction Q(x) = C { (1.6^0.5)Q1(x) - (2.4^0.5)Q2(x)}. The user initially calculates C as i(1.2)^0.5, leading to C^2 being -5/4, which raises the question of the validity of an imaginary normalization constant. The consensus is that the normalization condition requires the integral of the squared wavefunction to equal one, and since Q1 and Q2 are orthogonal, the correct normalization leads to C^2 = 5/20.

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Ruddiger27
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Homework Statement



A one-dimensional system is in a state at time t=0 represented by:

Q(x) = C { (1.6^0.5)Q1(x) - (2.4^0.5)Q2(x)}

Where Qn(x) are normalised eergy eigenfunctions corresponding to different energy eigenvalues, En(n=1,2)

Obtain the normalisation constant C


The Attempt at a Solution



I get C= i(1.2)^0.5 from the following equation:

C^2 * (1.6 (int( Q1 ^2 dx) - 2.4(int ( Q2 ^2 dx = 1

So C^2 has to be -5/4 in order for the above to be true. Is this right?
Just a bit confused over whether it's possible to have an imaginary value for the normalisation constant? Thanks for any help you can give.
 
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You haven't formed the product Q(x)Q*(x) correctly. What is special about energy eigenstates?
 
they follow linear superposition? so the integral of the total wavefunction squared is equal to the integral of 1.6*Q1^2 plus the integral of 2.4*Q2^2?
 
What is Q* equal to ? How do you define the scalar product?

Daniel.
 
Well there aren't any imaginary parts to the first wavefunction since its just in the form Q = C ( XQ1 - YQ2) so Q* is just the same as Q.
 
Ruddiger27 said:
they follow linear superposition?
What do you know about the integral of Q1Q2*?

so the integral of the total wavefunction squared is equal to the integral of 1.6*Q1^2 plus the integral of 2.4*Q2^2?
Yes. Are you absolutely clear why this is so?
 
I would think the integral of Q1Q2* would be zero since these wavefunctions are orthogonal, so I would end up with C^2 =5/20.
 

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