Is it Possible to solve Exponential Equations like these?

Click For Summary
SUMMARY

The discussion centers on solving the exponential equation 8000 - 1.2031 * e^(0.763x) = 0.5992 * e^(0.7895x). It is established that algebraic methods are insufficient for solving such transcendental equations. Instead, numerical or graphical solutions are recommended, with iterative trial values of x being the most effective approach. A suggested approximation indicates that x is likely around 10, which can be refined by rewriting the second exponential term.

PREREQUISITES
  • Understanding of exponential functions and their properties
  • Familiarity with transcendental equations
  • Basic knowledge of numerical methods for solving equations
  • Experience with graphical analysis of functions
NEXT STEPS
  • Explore numerical methods for solving transcendental equations
  • Learn about graphical solutions using software like Desmos or GeoGebra
  • Study the concept of iteration in numerical analysis
  • Investigate the properties of exponential growth and decay models
USEFUL FOR

Students studying mathematics, particularly those focused on calculus and differential equations, as well as educators and anyone interested in modeling exponential growth and decay scenarios.

Alex Myhill
Messages
5
Reaction score
0

Homework Statement


Hi, I have come across this equation in modelling exponential growth and decay. I am wondering if it is possible to solve it algebraically or not?

Homework Equations


8000-1.2031 * e^ (0.763x)=(0.5992×e^0.7895x)

The Attempt at a Solution


Brought all e^(ax) values to one side, however beyond that step I am really not sure of where to go, have looked at the problem for several hours without any results, any help would be appreciated.
 
Physics news on Phys.org
Alex Myhill said:

Homework Statement


Hi, I have come across this equation in modelling exponential growth and decay. I am wondering if it is possible to solve it algebraically or not?

Homework Equations


8000-1.2031 * e^ (0.763x)=(0.5992×e^0.7895x)

The Attempt at a Solution


Brought all e^(ax) values to one side, however beyond that step I am really not sure of where to go, have looked at the problem for several hours without any results, any help would be appreciated.
In general, there is no algebraic method to solve such equations since they are transcendental rather than algebraic by nature.

Only a numerical or graphical solution can be obtained. Iteration using different trial values of x is probably the quickest way to find a solution here.
 
Hi SteamKing, thankyou for your answer, I have learned something from that.
 
In this particular equation, you can easily see that the second exponential expression is likely to be about half the first, so x must be about 10.
You could then rewrite the .7895x as .763x+.0265x, or approximately .763x+0.265. That should get you to a reasonably accurate answer. You could redo that with the more accurate x value as a check.
 

Similar threads

  • · Replies 17 ·
Replies
17
Views
3K
  • · Replies 5 ·
Replies
5
Views
3K
Replies
9
Views
2K
  • · Replies 7 ·
Replies
7
Views
3K
  • · Replies 12 ·
Replies
12
Views
2K
  • · Replies 5 ·
Replies
5
Views
2K
  • · Replies 3 ·
Replies
3
Views
4K
Replies
9
Views
2K
  • · Replies 2 ·
Replies
2
Views
8K
  • · Replies 2 ·
Replies
2
Views
2K