Is [itex]x = - lo{g_2}(x)[/itex] a complex number

friend · Jun 5, 2012

If I have a function such that [itex]x = - lo{g_2}(x)[/itex], then must x be a complex number? Thanks.

D H · Jun 5, 2012

There are complex solutions to this, but there is one solution that is real.

haruspex · Jun 5, 2012

At x = 1, LHS is the larger; at x = 1/2, RHS is the larger. Since both functions are continuous in that range, there must be a real solution between the two.

D H · Jun 5, 2012

haruspex said:

At x = 1, LHS is the larger; at x = 1/2, RHS is the larger. Since both functions are continuous in that range, there must be a real solution between the two.

That's the number I was thinking of.

xAxis · Jun 6, 2012

also, it is an equation, not a function

Is [itex]x = - lo{g_2}(x)[/itex] a complex number

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