Is My Approach to Finding Absolute Magnitude Correct?

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The discussion revolves around the correct approach to calculating absolute magnitude using specific equations. A participant initially made an error by changing a factor from 2.5 to 5 in their calculations, which was pointed out as a mistake. After correcting the exponential and addressing a sign error, the calculations were confirmed to be on the right track. The final analysis indicated that the star's absolute magnitude is smaller than the Sun's, suggesting it has a greater luminosity. Overall, the steps taken were validated, and the participant was encouraged to proceed with their calculations.
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Homework Statement


1.2.png
[/B]

Homework Equations


m1-m2[/SB]=2.5log(ι21)

m-M=2.5log (d/10)2

3. The Attempt at a Solution
1.2 answer.png


Not sure if my approach and answers are correct

Please help
 
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shanepitts said:

Homework Statement


View attachment 83971 [/B]

Homework Equations


m1-m2[/SB]=2.5log(ι21)

m-M=2.5log (d/10)2

3. The Attempt at a Solution
View attachment 83972

Not sure if my approach and answers are correct

Please help
First question: In your very first line with an equation, you changed the factor of 2.5 to a factor of 5 in front of the log. Why did you do this? This seems to be a mistake.
 
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nrqed said:
First question: In your very first line with an equation, you changed the factor of 2.5 to a factor of 5 in front of the log. Why did you do this? This seems to be a mistake.

I forgot the exponential: m-M=2.5log(d/10)2
 
shanepitts said:
I forgot the exponential: m-M=2.5log(d/10)2
AH yes, Ok.

EDIT: you seem to have made a sign mistake. In the exponential for the calculation of the luminosity, you should have

M_1 - M_2 = M_1 - ( m +1.99) = 5 -m - 1.99


Then your work looks good. You just need to plug in the value of m=2. The absolute magnitude of the star is smaller than the Sun's absolute magnitude (3.99 versus 5) so the star has a larger luminosity than the Sun's and your final expression agrees with this. All the steps look good.
 
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nrqed said:
AH yes, Ok.

EDIT: you seem to have made a sign mistake. In the exponential for the calculation of the luminosity, you should have

M_1 - M_2 = M_1 - ( m +1.99) = 5 -m - 1.99Then your work looks good. You just need to plug in the value of m=2. The absolute magnitude of the star is smaller than the Sun's absolute magnitude (3.99 versus 5) so the star has a larger luminosity than the Sun's and your final expression agrees with this. All the steps look good.

Thanks a bunch and sorry for the typo
 
shanepitts said:
Thanks a bunch and sorry for the typo
You are welcome. And no problem about the typo, I make typos all the time :-)

Patrick
 
Last edited:
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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