Is My Matrix Approach to Solving Linear Equations with Parameters Correct?

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Homework Help Overview

The original poster presents a system of linear equations with parameters involving three unknowns: x, y, and z. The equations are expressed in terms of a parameter t, and the poster is using a matrix approach with Gaussian elimination to find solutions that depend on t.

Discussion Character

  • Exploratory, Assumption checking

Approaches and Questions Raised

  • Participants discuss the validity of the matrix approach and the implications of the parameter t in the solutions. Some question the notation used for the denominator in the expressions for x, y, and z, while others clarify that the presence of t in the solutions is expected given the nature of the equations.

Discussion Status

The discussion is ongoing, with participants providing feedback on the original poster's approach and questioning specific aspects of the notation. There is acknowledgment that for certain values of t, the equations may lead to conflicting results, indicating a productive exploration of the problem.

Contextual Notes

Participants note that for t=0, the equations yield conflicting results, suggesting that the parameter t plays a significant role in determining the nature of the solutions.

monsmatglad
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Homework Statement


hi. i have a linear equation with parameters that i am trying to solve. unknowns are x, y and z.
(12-3t)x + 2y +2z =2
x +0*y +2z =0
12x + (2-t)y + (2-t)z = 12

i am using a matrix-approach with Gaussian-elimination, and my results (for values of t which allows for a specific solution) seem reasonable, but the the variables depend on t. is this correct, or will the answers be without the parameter t even if t is not specified. i believe i have seen a similar problem in one of my books where the solution is without the parameter t.

Homework Equations


am i getting it wrong?

The Attempt at a Solution


x= -(2t+20)/(3t2t), y= -(37t-110)/(3t2t), z= (t+10)/(3t2t)
 
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I think you're doing just fine. For every value of t (*) you have a different set of equations, so it's no wonder t appears in the solution.

(*) for t=0 you get conflicting equations, so it's not surprising there is no answer for x,y,z.
 
I am puzzled as to why you are writing "t^2t" rather than "t^3". Am I misunderstanding what you mean?
 
monsmatglad said:

The Attempt at a Solution


x= -(2t+20)/(3t2t), y= -(37t-110)/(3t2t), z= (t+10)/(3t2t)
Check the denominator. I think you just copied it wrong.
 

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