Is My Method for Calculating Pressure Difference in a Venturi Meter Correct?

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Gorz
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Homework Statement


Water flows through a venturi meter, with an inlet diameter of 25cm and a throat diameter of 15cm. The pressure difference is measured using a manometer, which displaces the mercury by 12mm on the throat side.


Homework Equations


Bernoulli's
Mass continuity
P=rho.g.h

The Attempt at a Solution


Handwritten working for a venturi meter problem: a sketch of a pipe narrowing with flow arrows, then diameters 0.25 m and 0.15 m, static pressure from a manometer (ΔP = 13600 × 9.81 × 0.012 = 1600.992 N/m²), Bernoulli's equation and continuity giving V2 = 2.778 V1.

Handwritten working on lined paper: 2.778V1^2 - V1^2 = 2(1600 x 0.012), then 6.717284V1^2 = 3.2, V1 = sqrt(3.2/6.717284), V1 = 0.69 m s^-1, mass flow in = rho A V = 1000 x (0.25^2 pi / 4) x 0.69 = 33.87 kg/s.


Is this correct? I have no answers available as its from a past paper. My exam is tommorow and I would just like to clarify that the method I have used to find the pressure difference is correct.

Thanks.
 
No one able to help with this?

My exam is tommorow morning and I wouldn't mind some closure on my quiery.