Is RMS Voltage or Peak Voltage Used for Working Resistance?

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SUMMARY

The discussion clarifies that for calculating the working resistance of a heating element connected to an AC mains supply, the RMS voltage should be used. The user calculated the peak voltage (V0) from the given RMS voltage (230V-RMS) and determined the current using the power equation (P=IV). The final resistance calculated was 88.2 ohms, confirming that RMS values are essential for accurate calculations in AC circuits.

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  • Familiarity with Ohm's Law (V=IR)
  • Knowledge of power calculations (P=IV)
  • Basic algebra for manipulating equations
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[SOLVED] Working Resistance, Vo or VRMS

Homework Statement



Hey everyone, I'm new here and just wondering if you can give me a helping hand. In my Physics homework, the following question is stated:

"A heating element for an electric fire consists of a single strand if nichrome wire wound around an insulator. The heater is required to produce 1.2kW when connected to the 230V-RMS ac mains.

(i) Calculate the working resistance of the nichrome wire.

Okay, so it's not that i don't understand how to do the question, it's just that i don't know what it's asking for. Normally it would be okay, but because the 'RMS' was thrown in, it's put me off a bit.

Homework Equations



Equations used:

V0 = V-RMS × √2 ------Part 1
P=IV, therefore I=P/V ------Part 2
V=IR, therefore R=V/I ------Part 3


The Attempt at a Solution



Part 1 ---- V0 = 230v × √2 = 325.269v...
Part 2 ---- I = 1200w/325.269v... = 3.689A...
Part 3 ----325.269v.../3.689A..., therefore R = 88.2 ohms

Simply, what voltage do i use? Do i convert the V-RMS into V0, or leave it alone. I've tried both ways, the latter (not seen here), gives a resistance of 44.06 ohms.

All help is greatly appreciated. Thanks.
 
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RMS means "root mean square." Or the square root of the average of the squares of the the values. It is another method of finding an "average." When doing ac circuits, you use the RMS "average" values for current and voltage, etc, when plugging into the standard Ohm's Law and Power equations.

So, in short, use the RMS voltage.
 
Thanks very much for your response, now you say it, it has become much more clear as to why i would use that value. Again, thank you Chi Meson.
 

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