Is S^{c} the key difference in this logical equivalence?

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Is it equivalent?
[tex] ( \forall x \in S \forall y P(x) ) <=> \neg ( \exists x \in S^{c} \exists y \neg P(x) )[/tex]

Attempt at solution
I think it should be
[tex] ( \forall x \in S \forall y P(x) ) <=> \neg ( \exists x \in S \exists y \neg P(x) )[/tex]
The diiference to the above statement is [tex]S^{c}[/tex].
 
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Yes, your statement is correct.
 


HallsofIvy said:
Yes, your statement is correct.

Please, can you clarify whether it is the first statement or my attempt at solution?