Is sqrt(4) Equal to +2 or -2 and Where Is the Error in My Calculation?

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Discussion Overview

The discussion revolves around the interpretation of the square root of 4, specifically whether sqrt(4) should be considered as +2 or -2, and where errors may lie in the calculations presented by participants. The scope includes mathematical reasoning and clarification of concepts related to square roots.

Discussion Character

  • Mathematical reasoning
  • Conceptual clarification
  • Debate/contested

Main Points Raised

  • One participant asserts that sqrt(4) = +2 or -2 and questions where their reasoning goes wrong, suggesting a misunderstanding in the manipulation of square roots.
  • Another participant states that 2 = |sqrt(4)|, indicating a realization about the absolute value of the square root.
  • Several participants highlight that while both +2 and -2 are solutions to the equation x^2 = 4, the notation sqrt(4) conventionally refers to the principal (positive) square root, which is +2.
  • It is noted that the step involving sqrt(-1*-1*4) leading to -1*sqrt(4) is problematic, as the property sqrt(A*B) = sqrt(A) * sqrt(B) only holds under certain conditions (A and B must be non-negative).

Areas of Agreement / Disagreement

Participants generally agree that sqrt(4) is defined as +2, but there is a recognition that -2 is also a solution to the equation x^2 = 4. The discussion reflects multiple views on the manipulation of square roots and the conditions under which certain mathematical properties apply, indicating that the topic remains somewhat contested.

Contextual Notes

The discussion reveals limitations in understanding the properties of square roots, particularly regarding the conditions under which certain mathematical operations are valid. There is also a lack of consensus on the interpretation of the square root notation in this context.

luxiaolei
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2 = sqrt(4) = sqrt(-1*-1*4) = sqrt(-1)*sqrt(-1)*sqrt(4) = -1*sqrt(4) = -2 ?


Where am I wrong? sqrt(4) = +2 or -2 in the last step? but see sqrt(4)=-1*sqrt(4), still wrong..

Thanks in advance
 
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Feldoh said:
2 = |sqrt(4)|

Thanks!,how silly am I...gosh...
 
luxiaolei said:
2 = sqrt(4) = sqrt(-1*-1*4) = sqrt(-1)*sqrt(-1)*sqrt(4) = -1*sqrt(4) = -2 ?


Where am I wrong? sqrt(4) = +2 or -2 in the last step? but see sqrt(4)=-1*sqrt(4), still wrong..

Thanks in advance

The real problem here lies in the first step, not the last. 2 is a solution to √4, but is not the solution. Your conundrum has simply re-stated that -2 is also a solution to √4. This string of equations does not prove that 2 = -2 (obviously), only that the solution to √4 is non-unique. Good luck!
 
Thanks Unit91Actual!
 
Unit91Actual said:
The real problem here lies in the first step, not the last. 2 is a solution to √4, but is not the solution. Your conundrum has simply re-stated that -2 is also a solution to √4. This string of equations does not prove that 2 = -2 (obviously), only that the solution to √4 is non-unique. Good luck!

[itex]x^2 = 4[/itex] has two solutions, but sqrt(4) means the positive solution of this equations.
The other one is -sqrt(4).
2 = sqrt(-1 * -1 * 4) is OK, but the next step is not since sqrt(A*B) = sqrt(A) * sqrt(B) is only valid if A and B are >= 0
 
willem2 said:
[itex]x^2 = 4[/itex] has two solutions, but sqrt(4) means the positive solution of this equations.
The other one is -sqrt(4).
2 = sqrt(-1 * -1 * 4) is OK, but the next step is not since sqrt(A*B) = sqrt(A) * sqrt(B) is only valid if A and B are >= 0

Good point.
 

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