Is the Beta Decay Mass Condition Dependent on Atomic Masses?

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Discussion Overview

The discussion revolves around the conditions for beta decay, specifically positron emission, and the implications of atomic versus nuclear masses in this context. Participants also explore related questions about stability in isobars and the conservation laws involved in the decay process.

Discussion Character

  • Technical explanation
  • Debate/contested
  • Homework-related

Main Points Raised

  • One participant questions the mass condition for beta decay, suggesting that the atomic mass of the parent must exceed the sum of the daughter mass and twice the mass of an electron.
  • Another participant clarifies that the condition involves atomic masses, indicating that one electron mass accounts for the emitted electron and the other for an additional electron in the outer shell.
  • A different viewpoint suggests that if nuclear masses are considered, the condition would change to the parent mass being greater than the daughter mass plus one electron mass.
  • Participants discuss the implications of lepton number conservation in the decay process, questioning whether a proton could decay into a neutron and a positron while conserving charge.
  • One participant provides examples of different types of beta decay, referencing specific decay percentages for Cu64.
  • Questions arise about the source of the additional electron in the atomic shell, with some arguing that its origin is irrelevant to the mass condition being discussed.

Areas of Agreement / Disagreement

Participants express differing views on the interpretation of the mass condition for beta decay, with no consensus reached on whether atomic or nuclear masses should be used. The discussion remains unresolved regarding the implications of these interpretations and the related questions posed.

Contextual Notes

There are unresolved assumptions regarding the definitions of atomic versus nuclear masses and the implications for the decay process. Additionally, the source of the electron added to the atomic shell remains unclear and is debated among participants.

Master J
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In beta decay, positron emission, how come the condition for decay is:

M_p > M_d + 2m_e

Thats: atomic mass of parent > "daughter + twice the mass of an electron.

I'm sure there is some simple way of showing it, but I can't seem to find it!

Also, is the most stable isobar on an atomic mass parabola the most stable one? It's a question my lecturer posed to us, and I have been thinking about it a while.

Thanks!
 
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It is 2m_e because it is the atomic and not the nuclear mass.
One m_e is because of the electron emitted by the nucleus.
The second m_e is the extra electron that must be added to the outer shell of electrons in the atom.
 
that is since the daughter nucleus will have one electron less than the parent, and what is listed is ATOMIC masses. So if you calculate it with NUCLEAR masses it should of course be:

M_p > M_d + m_e

if now M is nuclear masses.

The other question is a homework - course work question, and should not be adressed in this forum but in the homework forum, with an attempt to solution.
 
"Also, is the most stable isobar on an atomic mass parabola the most stable one?"
As you write this question it is a tautology: Is the most stable the most stable?
 
For the parent p to decay to the daughter d by positron decay, the parent would have to create both a positron and electron (lepton number is conserved) before having sufficient energy to decay by positron emission. Example: could a proton decay to a neutron plus positron? What would the minimum proton mass be?
 
Bob S said:
For the parent p to decay to the daughter d by positron decay, the parent would have to create both a positron and electron (lepton number is conserved) before having sufficient energy to decay by positron emission. Example: could a proton decay to a neutron plus positron? What would the minimum proton mass be?

nope, the electron number is conserved by emitting a neutrino

beta+ decay on subnuclear level is:

p -> n + e(+) + neutrino

You are proposing:

p-> n + e(+) + e(-)

which violates electric charge conservation.
 
malawi_glenn said:
nope, the electron number is conserved by emitting a neutrino

beta+ decay on subnuclear level is:

p -> n + e(+) + neutrino

You are proposing:

p-> n + e(+) + e(-)

which violates electric charge conservation.
Mea Culpa. There are three types of beta decay exibited by nuclei: Here are 3 examples, all from Cu64
A) Positron emission (by proton), with an antineutrino
B) Electron emission (by neutron) , with a neutrino
C) K-shell electron capture (by proton) with only an antineutrino emission

(From Wiki):
64Cu has a half-life of 12.701 ± 0.002 hours and decays by 17.86 (± 0.14)% by positron emission, 39.0 (± 0.3)% by beta decay, 43.075 (± 0.500)% by electron capture
 
where does the electron that must be added to the shell then come from? if its from outside the atomic system in question, then surely it has no place in the mass condition?
 
Master J said:
where does the electron that must be added to the shell then come from? if its from outside the atomic system in question, then surely it has no place in the mass condition?


WHERE it comes from is not important, the issue is that you are using atomic masses.. as I explain to you.
 

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