Is the Calculation of Thermal Energy in Mixing Water and Steam Accurate?

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Homework Help Overview

The discussion revolves around the calculation of thermal energy when mixing water and steam, specifically focusing on the heat transfer involved in the process. The subject area includes thermodynamics and heat transfer principles.

Discussion Character

  • Exploratory, Assumption checking

Approaches and Questions Raised

  • Participants discuss the calculation of heat transfer, questioning the mass of steam involved and the assumptions made in the problem setup.

Discussion Status

Some participants have provided guidance on significant figures and the importance of prefixes in calculations. There is an acknowledgment of a potential oversight regarding the mass of steam, indicating an ongoing exploration of the problem's parameters.

Contextual Notes

The original poster's calculation is based on specific values stated in the problem, which some participants are verifying and clarifying.

physicsstudent111
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Homework Statement
How much energy is required to change one quarter of 8.0 kg of water at 25 degrees celsuis into steam(100 degrees celcuis)
Relevant Equations
Q=mct
Q=mLv
Q=Qwarm water+Qsteam
Q=mct+mLv
Q=(8kg)(4200J)(100C-25C)+(2kg)(2.3*10 to the power of 6 J/Kg)
Q=7.12*10 to the power of 6 J
Is this the correct answer?
 
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Why only 2kg water turning to steam?
 
Because that's what the question states
 
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Ah great, I missed the one quarter.

Answer is correct. Keep in mind correct significant digits and usage of prefix
 
Last edited:
Thank you!
 
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