Is the Cartesian Product of Two Countable Sets Countable?

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The discussion focuses on proving that the Cartesian product of two countable sets, A and B, is also countable. It emphasizes the need to establish a bijection to demonstrate countability, suggesting that each element can be labeled with natural numbers. A diagonal argument is mentioned as a common method to illustrate this correspondence by arranging elements in a grid. Additionally, it notes that the finite product of countable sets is countable, referencing the fundamental theorem of arithmetic for support. Understanding these concepts is crucial for successfully completing the proof.
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Homework Statement



Definition:. Let A and B be sets. The Cartesian product AXB of A and B is the set of ordered pairs (a, b)

(3) Assume that A and B are countable sets. Prove that the Cartesian product A x B is countable.

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The Attempt at a Solution



I know that to prove that something is countable, you need to check if the function is a bijection, which I know how to do. However, I am having a little trouble understanding what the function for this question would be. Would it be:

f:AxB------>AxB where
f(AxB)=(A,B)?
 
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Since each set is countable, they can be put into 1-1 correspondence with the naturals. That is, you can 'label' each element using the naturals. One proof for this exercise uses a diagonal argument - that is you can arrange all the elements into a grid and show correspondence between diagonal entries. This is not very intuitive but it is used often so you can ask your prof or consults a real analysis book for further discussion.
Another exercise that is useful is to show that the finite product of countable sets is countable. This proof makes use of the fundamental theorem of arithmetic
 
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