Is the Compton wavelength equal to 2*pi*r, the radius of an electron?

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SUMMARY

The discussion centers on the relationship between the Compton wavelength and the radius of an electron. Stephen asserts that the Compton wavelength, defined as λ = h/mc, can be equated to 2πr, leading to the conclusion that r = h/(2πmc). This derivation is based on the principles of quantum angular momentum, specifically L = mvr = h/2π. The conclusion drawn is that the Compton wavelength can indeed represent the radius of an electron in this context.

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StephenD420
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Hello all

I have a quick question regarding the derivation of the radius of an electron using the compton wavelength.
Is the following true?
λ = h/mc
where 2*pi*r = λ from quantum angular momentum L = mvr = h/2pi -> mcr = h/2pi -> 2pi*r = h/mc = λ ??
so
r = h/(2*pi*m*c)
?

I just want to make sure that the compton wavelength can be equal to 2*pi*r, where r is the radius of an electron, which is what I am trying to find.

Thanks
Stephen
 
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Am I correct in my thinking about the electron radius?

Thanks,
Stephen
 

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