Is the Current Calculation in the Circuit Incorrect?

[Miike012]

I think the book is wrong.

Why is the current (which they denote I_L) equal to V_s/(R_eq)

Where V_s = 458.3kV and R_eq is the equivalent resistance of the circuit equal to the sum of the two resistors in series ( R_eq = 220 + 20 = 240).

In there equation they left out the the resistor of 20 ohmes

 

[barryj]

No, the book answer is correct. They are finding the current in Rload by knowing Iload = Vload/Rload.
Now that you know the current, you can find the voltage drop across the 20 okm line resistance. Then you can find the source voltage.

 

[Miike012]

No, the book answer is correct. They are finding the current in Rload by knowing Iload = Vload/Rload.
Now that you know the current, you can find the voltage drop across the 20 okm line resistance. Then you can find the source voltage.

Why is the current different through each resistor?

 

[Dick]

Why is the current different through each resistor?

It's not. That's what barryj is saying. They are the same. But the voltage drop is only measured against the load resistance. You can use that to find the source voltage.