High School Is the derivative of a function everywhere the same on a given curve?

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The derivative of a function can vary at different points along a curve, particularly for curved lines, where the slope changes. While a straight line has a constant slope, curved functions like f(x) = x^2 have derivatives that are consistent in form (2x) but vary in value depending on x. It's important to note that not all functions have simple derivative equations, and some can exhibit complex behavior. The discussion also clarifies that the graph of f(x) = x^2 does not have a vertical asymptote, contrasting it with functions like f(x) = 1/x^2, which do. Understanding these concepts is crucial for grasping calculus fundamentals.
Debaa
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Is the derivative of a function everywhere the same on a given curve? Or is it just for a infinitesimally small part of the curve? Thank you for the answer.
 
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It can be different for each infinitesimally small part of the curve. (It might be the same but not necessarily so.) The derivative at a point on the curve is the slope of the curve at that point. A straight line has the same slope everywhere. A curved line has different slopes (i.e. derivative) at different points.
 
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But at other points the function is the same so wouldn't by power rule the derivative be same??
 
I should be more clear. The value of the derivative can be different at different points. It may have the same equation, but not the same value. A lot of functions and their derivatives do not have a nice equation form, so you should not count on that in general.
 
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Well f(x) = x^2 is vertically asymptotic. And it's derivative is always 2x isn't it? Will it be 2x everywhere? (I am new to calculus so pls bare.)
 
Debaa said:
Well f(x) = x^2 is vertically asymptotic. And it's derivative is always 2x isn't it? Will it be 2x everywhere? (I am new to calculus so pls bare.)
Yes, you are right. f'(x) = 2x for any value of x.
 
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Yes, you are right. The derivative is 2x for every value of x.
You can see in the following graph that for every value of x, the slope of f(x)=x2 is d(x)=2x.
temp.png
 
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So as x changes derivative changes. Thanks.
 
Debaa said:
Well f(x) = x^2 is vertically asymptotic.
Not sure what you mean by this. The graph of y = x2 does not have a vertical asymptote, although as x gets larger (or more negative) the y value gets larger.

The graph of y = 1/x2 does have a vertical asymptote at x = 0.
Debaa said:
And it's derivative is always 2x isn't it? Will it be 2x everywhere? (I am new to calculus so pls bare.)
 
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My bad
 

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