Is the Derivative of f(x)=1/x^3 Correctly Calculated as -3/x^4?

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SUMMARY

The derivative of the function f(x) = 1/x^3 is correctly calculated as f'(x) = -3/x^4. This conclusion is confirmed by multiple participants in the forum discussion, establishing the accuracy of the differentiation process. The topic is appropriate for the Calculus forum, as it pertains to fundamental differentiation techniques.

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DeusAbscondus
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Hello folks,
I simply wish to confirm that the following is correct:

If $f(x)=\frac{1}{x^3}$ then $f'(x)=-\frac{3}{x^{4}}$

Thanks kindly,
DeusAbs

PS Does this most basic of questions properly belong elsewhere; if so, please tell me someone. Perhaps in pre-calculus?
 
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DeusAbscondus said:
Hello folks,
I simply wish to confirm that the following is correct:

If $f(x)=\frac{1}{x^3}$ then $f'(x)=-\frac{3}{x^{4}}$

Thanks kindly,
DeusAbs

PS Does this most basic of questions properly belong elsewhere; if so, please tell me someone. Perhaps in pre-calculus?

Correct! (Clapping)
 
DeusAbscondus said:
Hello folks,
I simply wish to confirm that the following is correct:

If $f(x)=\frac{1}{x^3}$ then $f'(x)=-\frac{3}{x^{4}}$

Thanks kindly,
DeusAbs

PS Does this most basic of questions properly belong elsewhere; if so, please tell me someone. Perhaps in pre-calculus?

Any questions on differentiation belong in the Calculus forum.
 

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