Is the Determinant of a Covariant Tensor of Order 2 an Invariant of Weight 2?

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SUMMARY

The determinant of an absolute covariant tensor of order 2, denoted as A = det(Aij), is established as an invariant of weight 2. Additionally, the tensor A itself is classified as an invariant of weight 1. The transformation rules from barred to unbarred tensors are crucial for understanding these invariants. Reference to "Tensors, Differential Forms, and Variational Principles" by Lovelock and Rund provides foundational definitions and context for these concepts.

PREREQUISITES
  • Understanding of covariant tensors, specifically absolute covariant tensors of order 2.
  • Familiarity with the concept of invariants and their weights in tensor analysis.
  • Knowledge of tensor densities and their properties.
  • Ability to apply transformation rules for tensors in mathematical physics.
NEXT STEPS
  • Study the transformation rules for tensors, focusing on the transition from barred to unbarred forms.
  • Explore the definitions and implications of tensor densities, particularly in relation to weight.
  • Read "Tensors, Differential Forms, and Variational Principles" by Lovelock and Rund for a deeper understanding of tensor invariants.
  • Investigate practical applications of covariant tensors in differential geometry and theoretical physics.
USEFUL FOR

This discussion is beneficial for students and professionals in mathematics, physics, and engineering who are working with tensor analysis, particularly those focusing on differential geometry and the properties of covariant tensors.

anotherann
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Question: Let Aij denote an absolute covariant tensor of order 2. Show that the determinant A = det(Aij ) is an invariant of weight 2 and A is an invariant of weight 1.

I have little clue about this question. Would writting down the transformation rule from barred to unbarred 2nd-order tensor work? Any help would be greatly appreciated! Thanks!

Homework Statement




Homework Equations





The Attempt at a Solution

 
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anotherann said:
Question: Let Aij denote an absolute covariant tensor of order 2. Show that the determinant A = det(Aij ) is an invariant of weight 2 and A is an invariant of weight 1.
This makes no sense- "Show that A is an invariant of weight 2" and "A is an invariant of weight 1".

I have little clue about this question. Would writting down the transformation rule from barred to unbarred 2nd-order tensor work? Any help would be greatly appreciated! Thanks!

Homework Statement




Homework Equations





The Attempt at a Solution

What are the definitions of "invariant of weight 2" and "invariant of weight 1"?
 
The determinant of a (0,2) tensor is a tensor density of weight 2. See, for example, page 41 of Tensors, Differential Forms, and Variational Principles by Lovelock and Rund.
 

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