What the title says. Acting on a fermionic state with the number operator to a power is like acting with the fermionic operator itself. Does this allow us to define ## \hat{n}^k=\hat{n} ##? Or is there any picky mathematical reason not to do so?(adsbygoogle = window.adsbygoogle || []).push({});

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# I Is the Fermion number operator squared equal to itself?

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