Is the Gravitational Constant a Tensor or a Constant Derived from Experiment?

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Discussion Overview

The discussion revolves around the nature of the gravitational constant in Newton's equations, specifically whether it is a tensor related to the curvature of spacetime or a scalar constant derived from experimental measurements. The conversation touches on theoretical implications and dimensional analysis.

Discussion Character

  • Exploratory
  • Technical explanation
  • Conceptual clarification

Main Points Raised

  • One participant questions if the gravitational constant is a description of spacetime curvature, suggesting it could be a tensor.
  • Another participant asserts that it is primarily a scalar constant derived from experiments, but notes its role as a conversion factor between energy and spacetime curvature.
  • A participant inquires about the units of the gravitational constant, asking if they exist solely for dimensional analysis.
  • Another participant clarifies the units of the gravitational constant as m3 s-2 kg-1 and explains how these units relate to the force in Newton's equation.

Areas of Agreement / Disagreement

Participants express differing views on the nature of the gravitational constant, with some supporting the idea of it being a scalar constant while others explore the possibility of it being a tensor. The discussion remains unresolved regarding its classification.

Contextual Notes

There are limitations in the discussion regarding the assumptions about the gravitational constant's role in physics and its relationship to spacetime curvature, which are not fully explored.

khemist
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Is the gravitational constant in Newton's equations a description of the curvature of space time? if it is, does that mean it is a tensor, or simply a constant derived from experiment?
 
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Its mostly the latter---a scalar constant derived from experiment. But it does have a more physical meaning: its the term that multiplies the stress-energy tensor, so its a conversion factor between standard units of energy and the curvature of space-time.
 
does that mean the constant has units, say of Newtons?

edit: i just looked at wikipedia, and it says it has units or N(m/kg)^2.

Are those units there to simply make the dimensional analysis work?
 
No, its has units of [tex]m^3 s^{-2} kg^{-1}[/tex] in mks, which is force times distance squared over mass squared

Just think about how you could end up with a force in Newton's equation [tex]F_g = G \frac{m_1 m_2}{r^2}[/tex]
 
sweet thanks for the quick replies.
 

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