Is the Image Formed by a Concave Lens Real or Virtual?

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Homework Help Overview

The discussion revolves around the nature of the image formed by a concave lens when a convergent beam is incident upon it. Participants are examining whether the image is real or virtual based on the properties of concave lenses and the behavior of light rays passing through them.

Discussion Character

  • Conceptual clarification, Assumption checking

Approaches and Questions Raised

  • The original poster attempts to apply the lens formula and magnification concepts to determine the nature of the image. Some participants question the validity of the question itself and the assumptions made regarding the behavior of light rays through a concave lens.

Discussion Status

Participants are exploring different interpretations of the problem, with some suggesting that the question may be flawed. There is a recognition of the original poster's mathematical approach, but also a critique of the assumptions leading to the conclusion of an infinite image distance.

Contextual Notes

There is an indication that the question may lack clarity, particularly regarding the behavior of rays through a diverging lens and the implications for image formation. The discussion reflects on the definitions of real and virtual images in the context of lens optics.

Amith2006
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# A convergent beam is incident on a concave lens as shown in figure. Which of the following is not correct?
a) The image formed is real
b) The image formed is virtual
c) The image formed is erect
d) The image formed is magnified
I solved it in the following way:

Let f be the focal length of the concave lens and let v be the image distance. From the figure, object distance = -f(virtual object), Focal length = -f(focal length of concave lens is negative)
(1/ object distance) + (1/image distance) = 1/ Focal length
(1/-f) + (1/v) = 1/-f
Solving I get,
v = + infinity
Magnification = -v/u = (- infinity)/(-f)
= + infinity
Since Magnification is positive the image is erect. Since the Magnification is infinity the image is magnified. Since the image distance is positive the image is real. So the answer is (b). Is my argument right?
 

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What a bizarre question.

First of all, you don't need the math. Look at the drawing and determine "what happens to rays that go through a diverging lens if those rays are heading toward the far focal point." This is one of the basic principal rays for diverging lenses.The result is that both rays emerge parallel to the principle axis. Parallel rays do not intersect to form real or virtual images. There is no image here, and that is why you got the infinite image distance. The question is flawed but your work is impressive.
 
Chi Meson said:
What a bizarre question.

First of all, you don't need the math. Look at the drawing and determine "what happens to rays that go through a diverging lens if those rays are heading toward the far focal point." This is one of the basic principal rays for diverging lenses.


The result is that both rays emerge parallel to the principle axis. Parallel rays do not intersect to form real or virtual images. There is no image here, and that is why you got the infinite image distance. The question is flawed but your work is impressive.
In the case of a convex lens, if an object is placed at its first principal focus, the light rays from the object after passing through the lens is rendered parallel. We then say that the a real, inverted and extremely magnified image is formed at infinity. Can't we say the same thing in the case of concave lens?
 
Please respond.
 

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