Is the Mass of My Birthday Pulley Evenly Distributed?

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SUMMARY

The discussion centers on determining whether a 12 cm diameter, 2 kg pulley is uniformly distributed in mass. By conducting an experiment with a 1 kg book suspended 1 m above the floor, the user calculated the book's acceleration to be -3.97 m/s², assuming a uniform pulley. However, further calculations revealed that the actual acceleration was -9.80 m/s², indicating that the pulley is not uniform. The user concludes that the difference in calculated accelerations suggests mass concentration within the pulley, although they seek further insights on the implications of this finding.

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  • Understanding of moment of inertia, specifically I = 0.5MR² for disks.
  • Knowledge of torque calculations and their relation to angular acceleration.
  • Familiarity with kinematic equations, particularly x = x₀ + v₀t + 0.5at².
  • Basic principles of forces and Newton's second law of motion.
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Homework Statement


You have been given a pulley for your birthday. It is 12 cm in diameter and has a mass of 2 kg. You get to wondering whether the pulley is uniform. That is, is the mass evenly distributed, or is concentrated toward the center of near the rim? To find out, you hang the pulley on a hook, wrap a string around it, and suspend you 1 kg physics book 1 m above the floor. With your stopwatch you find that it takes .71 s for the book to hit the floor. What can you conclude about the pulley


Homework Equations


Moment of Inertia for a disk I=.5MR^2
Torque=rFt=I * angular acceleration(alpha)
x=xo + volt+ .5at^2


The Attempt at a Solution



First of all, Is my work correct?


Okay so I calculated the acceleration of the book:

0m=1m + .5*a*(.71s)^2
a= -3.97 m/s^2

Then I decided to calculate the acceleration of the book as if the pulley were uniform:

I=.5(2kg)(.06m)^2 I= .0036 kgm^2
Torque=(.06m)*(T) = (.0036)*alpha
T=.06*alpha
alpha=-a/r
T=(.06)*(-a/.06) = -a


Sum of Forces on y for book = T-mg=ma
Making the substitution for T : -a-mg=ma
-mg= ma +a
-(1.0kg)(9.80)= a(1kg +1)
a= -9.80 m/s^2

Since the two calculated accelerations are different, the pulley must not be uniform. But I don't know if I can make any conclusions further than this about where the mass must be concentrated.
 
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First of all, if the disk isn't uniform, the moment of inertia won't be [tex].5MR^2[/tex]. Beyond that, I'm about to fall over in my chair from being really tired, so I'll try and get back to you on the rest tomorrow. >_<
 

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