Is the Moment of Inertia Calculation Correct for a Solid Sphere in Space?

  • Thread starter Thread starter jumbogala
  • Start date Start date
  • Tags Tags
    Intertia Moment
Click For Summary
SUMMARY

The moment of inertia for a solid sphere with a mass of 2 kg and a radius of 5 m is calculated using the formula I = (2/5)MR². Substituting the values, I = (2/5)(2 kg)(25 m²) results in I = 50 kg·m². This calculation is confirmed as correct by participants in the discussion, affirming the straightforward application of the formula.

PREREQUISITES
  • Understanding of the moment of inertia concept
  • Familiarity with the formula for the moment of inertia of a solid sphere
  • Basic knowledge of mass and radius in physics
  • Ability to perform algebraic calculations
NEXT STEPS
  • Study the derivation of the moment of inertia formulas
  • Explore applications of moment of inertia in rotational dynamics
  • Learn about the moment of inertia for other geometric shapes
  • Investigate the effects of mass distribution on moment of inertia
USEFUL FOR

Students in physics, educators teaching mechanics, and anyone interested in understanding rotational motion and inertia calculations.

jumbogala
Messages
414
Reaction score
4

Homework Statement


A solid sphere of mass 2 kg and 5 m radius is in space. Find its moment of inertia.

Homework Equations

2
moment of inertia of a solid sphere about its diameter: [tex]\frac{2}{5}[/tex]MR2, where M is the mass of the sphere and R is its radius.

The Attempt at a Solution


I = mr^2 = (2 kg)(25 m^2) = 50 kgm^2

Is that right, or am I totally out to lunch? Seems too easy.
 
Last edited:
Physics news on Phys.org
Yes that looks correct to me.
 

Similar threads

  • · Replies 3 ·
Replies
3
Views
1K
Replies
335
Views
17K
Replies
11
Views
4K
Replies
8
Views
15K
Replies
17
Views
2K
  • · Replies 3 ·
Replies
3
Views
6K
  • · Replies 2 ·
Replies
2
Views
8K
  • · Replies 97 ·
4
Replies
97
Views
6K
Replies
16
Views
4K
Replies
8
Views
2K