Is the Moon's Orbit Influenced by Earth's Warped Space and Tidal Friction?

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SUMMARY

The Moon's orbit around Earth is influenced by gravitational forces and tidal friction, which causes it to gradually recede from Earth at a rate of a few centimeters per year. This phenomenon is a result of the Moon's high velocity, which allows it to maintain its orbit despite the gravitational pull of Earth. The discussion highlights that while the Moon is technically falling towards Earth, its orbital velocity keeps it in a continuous state of free fall, preventing a collision. Over billions of years, the Moon's distance from Earth may change due to complex gravitational interactions, but it will not escape Earth's orbit solely due to tidal effects.

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  • Understanding of gravitational forces and centripetal acceleration
  • Familiarity with orbital mechanics and Newton's laws of motion
  • Knowledge of tidal friction and its effects on celestial bodies
  • Basic grasp of Einstein's theory of general relativity and spacetime curvature
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  • Study the long-term evolution of celestial orbits in multi-body systems
  • Investigate the implications of general relativity on gravitational interactions
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I understand that the moon doesn't fall down because it is in an orbit around the Earth. Is this orbit created by warped space due to the mass of the earth?
 
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The velocity of the moon allows it to overcome (well, not completely overcome) the gravitational pull towards the earth. The gravitational pull itself is a centripetal acceleration (take a look at any circular motion physics problem). Eventually it will fall into the earth, just like we will eventually fall into the sun. At least, that's my understanding, which could be wrong.

Edit:
A quick google yields that the moon is a few cm further from the Earth each year, indicating that the velocity is exceeding the centripetal (gravity), and thus, over time, the moon should leave Earth instead of crashing into it.
 
Why is the velocity overcoming the centripetal force caused by gravity? Shouldn't it be vice versa, that the velocity is slowing down over time?
 
let's do a little though experiment. (let's also ignore air resistance since it should be negligible in space)

first, imagine standing on a hill and dropping a rock. it should fall straight down, no surprises.

now, imagine throwing it forward. it no longer falls straight down, it goes forward and curves down.

now, imagine throwing the rock even faster. the rock goes further. if you keep throwing the rock faster, it keeps going further.

on an infinite, flat world we could do this forever with greater speeds/distances. the earth, however, is curved.

if we zoom out some on our experiment so we can actually see the curvature of the earth, and we continue throwing our rock farther, it starts going farther and farther around the planet.

now, imagine throwing the rock so fast that it goes all the way around the Earth back to you. at this point it should be right where you first threw it and have the same velocity it initially had. that means it will continue around again... and again, and again, and again, etc.

this is essentially what orbit is. the object moves so fast that it falls around the planet.edit: so, in fact, the moon does fall down, it just has such a huge velocity in a different direction that the direction of the gravitational force on it (and therefore where "down" is) changes really fast as well.
 
Last edited:
kaiten said:
let's do a little though experiment. (let's also ignore air resistance since it should be negligible in space)

first, imagine standing on a hill and dropping a rock. it should fall straight down, no surprises.

now, imagine throwing it forward. it no longer falls straight down, it goes forward and curves down.

now, imagine throwing the rock even faster. the rock goes further. if you keep throwing the rock faster, it keeps going further.

on an infinite, flat world we could do this forever with greater speeds/distances. the earth, however, is curved.

if we zoom out some on our experiment so we can actually see the curvature of the earth, and we continue throwing our rock farther, it starts going farther and farther around the planet.

now, imagine throwing the rock so fast that it goes all the way around the Earth back to you. at this point it should be right where you first threw it and have the same velocity it initially had. that means it will continue around again... and again, and again, and again, etc.

this is essentially what orbit is. the object moves so fast that it falls around the planet.


edit: so, in fact, the moon does fall down, it just has such a huge velocity in a different direction that the direction of the gravitational force on it (and therefore where "down" is) changes really fast as well.

And a little pic to go with the explanation...
http://csep10.phys.utk.edu/astr161/lect/history/cannonS.jpg
 
QuarkCharmer said:
The velocity of the moon allows it to overcome (well, not completely overcome) the gravitational pull towards the earth. The gravitational pull itself is a centripetal acceleration (take a look at any circular motion physics problem). Eventually it will fall into the earth, just like we will eventually fall into the sun. At least, that's my understanding, which could be wrong.

Edit:
A quick google yields that the moon is a few cm further from the Earth each year, indicating that the velocity is exceeding the centripetal (gravity), and thus, over time, the moon should leave Earth instead of crashing into it.

Thanks!
This makes much more sense now,
 
a.alexandra said:
Thanks!
This makes much more sense now,

Actually, that's the part that's inaccurate. The moon will neither fall into Earth nor escape from it.

These effects are not unstable i.e. the fact that it's moving away does not mean it will just continue to move away. The Moon's distance from Earth is fraught with subtleties having to do with rotational rates and tides. The upshot is that the distance has changed over very long periods but it is not a runaway process.
 
Actually, the moon probably can potentially escape Earth orbit, it will just take billions of years longer than for the sun to go red giant. All bets are off when that happens.
 
  • #10
One could argue that the moon does fall down, it just keeps missing.
 
  • #11
Jim1138 said:
One could argue that the moon does fall down, it just keeps missing.

Perhaps we should rename Luna to Arthur Dent?
 
  • #12
Chronos said:
Actually, the moon probably can potentially escape Earth orbit, it will just take billions of years longer than for the sun to go red giant. All bets are off when that happens.

If the Sun, Earth and Moon remained as they are, the Earth's oceans remaining much the same, then the Earth will slow until it matches the Moon's orbital period and the Moon will recede to match the net angular momentum of the system. This state is reached when the Earth's day is 48.5 times the present day and the Moon is at a radius of 552,000 km. However the tidal braking from the Sun still occurs - it's 1/3 the Moon's tidal effect on the Earth and will be much stronger relatively as the Moon backs away. Since the Sun is still slowing the Earth down, eventually the Earth will be turning slower than the Moon and create a net drag on the Moon, causing it to begin a slow approach to the Earth. After about 15 billion years the two will be so close, that the Moon will break up into a ring of debris.

However the Earth, Sun and Moon are not alone. The other planets jostle the three with their gravity, introducing chaotic behaviour into their orbital evolution. Mercury especially could go wandering into the path of the other planets. Thus the Moon might escape, but not via tidal evolution alone.
 
  • #13
daveb said:
Perhaps we should rename Luna to Arthur Dent?
Darn! I was about to make that reference myself!:-p
 
  • #14
Thank you all, what great responses. I guess this would clarify my confusion (?) a bit: The work expended due to a Force active over a distance is described as W= ∫F°dL. So a force acting on an object over a certain length L is W. It seems that this doesn't apply with the force of Gravity because there is no real Work involved in the moon rotating around the Earth (if you discount the friction due to tides, which was an excellent point).

I think the answer to my question has to do with what Einstein said about gravity: that it is not a force per se, but a curve in Space-time, and it takes Relativity to explain it fully. From what I gather: from the perspective of the moon, it is really traveling in a straight line at a constant velocity (weird). Therefore Newton's first law of motion would apply and it will go on traveling at the same velocity for eternity (in the absence of another force). It just wigs me out to think of this.
 
  • #15
Chronos said:
JPL gives a pedagogical presentation on orbits at http://www2.jpl.nasa.gov/basics/bsf3-4.php. The moon is slowly receeding from Earth due to tidal friction, which is also slowing the rotation of earth.

The tidal friction thing is interesting. Would tidal friction not decrease during periods of heavy glaciation? If this were to be the case would the moons regression from Earth not slow down, cease or even reverse? Just a thought.
 
  • #16
daveb said:
Perhaps we should rename Luna to Arthur Dent?

:smile::smile::smile:
 
  • #17
Velikovsky said:
The tidal friction thing is interesting. Would tidal friction not decrease during periods of heavy glaciation? If this were to be the case would the moons regression from Earth not slow down, cease or even reverse? Just a thought.
It is the tidal effects on the solid Earth that have the major effect, not just the effects on the oceans.
 

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