Is the Multivariate Chain Rule Being Applied Correctly?

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SUMMARY

The discussion centers on the application of the multivariate chain rule in calculus, specifically in finding the partial derivative \(\frac{\partial z}{\partial y}\) for the function \(z=F(u,v,y)\), where \(u=f(v,x)\) and \(v=g(x,y)\). The original poster proposes a formula involving the derivatives of \(z\) with respect to \(u\) and \(v\), but references a textbook that presents a different formulation. The consensus among participants is that the textbook has likely confused the variables \(u\) and \(v\), affirming the poster's approach as correct.

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  • Understanding of multivariate calculus
  • Familiarity with partial derivatives
  • Knowledge of the chain rule in calculus
  • Ability to differentiate composite functions
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  • Review the multivariate chain rule in calculus
  • Practice finding partial derivatives of composite functions
  • Study examples of variable substitution in multivariable functions
  • Examine common mistakes in applying the chain rule
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Students and educators in mathematics, particularly those studying calculus, as well as anyone involved in advanced mathematical problem-solving and analysis.

Kreizhn
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Homework Statement


Find
[tex]\frac{\partial z}{\partial y} [/itex]<br /> where z=F(u,v,y), u=f(v,x), v=g(x,y).<br /> <br /> <h2>The Attempt at a Solution</h2><br /> If I remember multivariate calculus at all, this should be (please forgive the abuse of notation)<br /> <br /> [tex]\frac{\partial z}{\partial y} = \frac{\partial z}{\partial u}\frac{\partial u}{\partial v}\frac{\partial v}{\partial y} + \frac{\partial z}{\partial v}\frac{\partial v}{\partial y} + \frac{\partial z}{\partial y}[/tex]<br /> <br /> However, I have a book in front of me that says it should be<br /> <br /> [tex]\frac{\partial z}{\partial y} = \frac{\partial z}{\partial v}\frac{\partial v}{\partial u}\frac{\partial u}{\partial y} + \frac{\partial z}{\partial u}\frac{\partial u}{\partial y} + \frac{\partial z}{\partial y}[/tex]<br /> <br /> I think I'm correct and that they must have confused u and v. If someone could verify this for me it would be much appreciated.[/tex]
 
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I agree. It think they mixed up u and v.
 

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