Is the perimeter numerically equal to the area in this equation?

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The discussion centers on proving that the perimeter, represented by the equation (1/2)uv, is numerically equal to the area defined by the expressions for u, v, and w. The variables are defined as u = 2(m + n)/n, v = 4m/(m - n), and w = 2(m^2 + n^2)/(m - n)n. The approach suggested is to work indirectly from the final equation to the definitions of u, v, and w, ensuring that each step is reversible to validate the equality.

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mathdad
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If u = 2(m + n)/n, and v = 4m/(m - n), and

w = 2(m^2 + n^2)/(m - n)n, show that

(1/2)uv = u + v + w (that is, the perimeter is numerically equal to the area).

This question is basically a plug and chug situation.
I must multiply (1/2) by the given values of u and v on the left side. I must then replace u, v and w on the right side with their given values and add. The right side must = the left side, right?
 
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Yes, it looks like the simplest way to do this is NOT "directly", starting from the given values of u, v, and w and then showing the final equation, but "indirectly", starting from the final equation then working to the equations for u, v, and w. As long as every step is "reversible", that will prove what you want.
 
I will work this out when time allows. Interesting question.
 

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