AyoubEd Messages 10 Reaction score 2 Thread starter Jun 29, 2016 #1 please look at he underligned formula. is it a axiom we have to ake for granted ? Attachments 55.PNG 11.9 KB · Views: 577
Drakkith Mentor Messages 23,211 Reaction score 7,699 Jun 29, 2016 #2 No, we can and have measured this as far as I know.
AyoubEd Messages 10 Reaction score 2 Jun 29, 2016 #3 I think i got it E=h.v -De broglie : p=h/(the wace longitude:L) hence: E=h.c/L=p.c
jtbell Staff Emeritus Science Advisor Homework Helper 2025 Award Messages 16,110 Reaction score 8,478 Jun 29, 2016 #4 For relativistic particles, the general relationship between energy, momentum and mass is $$E = \sqrt {(pc)^2 + (mc^2)^2}$$ where m is the invariant mass (often called the "rest mass"). For photons, m = 0 which leads to E = pc.
For relativistic particles, the general relationship between energy, momentum and mass is $$E = \sqrt {(pc)^2 + (mc^2)^2}$$ where m is the invariant mass (often called the "rest mass"). For photons, m = 0 which leads to E = pc.