Is the Pion Emitted by a High-Energy Nucleon Real or Virtual?

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Homework Help Overview

The discussion revolves around the emission of a pion by a high-energy nucleon, specifically questioning whether the pion is real or virtual. The context involves particle physics and the conservation of energy and momentum in particle interactions.

Discussion Character

  • Conceptual clarification, Assumption checking, Mixed

Approaches and Questions Raised

  • Participants explore the conditions under which the pion can be considered real or virtual, with some suggesting that the excitation energy of the nucleon plays a crucial role. Questions are raised about the implications of the process being isolated and the criteria for determining the nature of the particles involved.

Discussion Status

The discussion is ongoing, with participants examining different interpretations of the problem. Some have provided mathematical hints and references to invariant mass equations, while others express frustration over potential misunderstandings of the original question. There is a recognition that the nature of the nucleon (excited or not) significantly alters the analysis.

Contextual Notes

Participants note that the process cannot occur in isolation, which raises questions about the virtual nature of particles involved. The distinction between excited and non-excited nucleons is also highlighted as a critical factor in the discussion.

malawi_glenn
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Homework Statement



Assume that a high-energy nucleon is emitting a pion, i.e. the process N→N+π. Is the pion real or virtual or both? Motivate your answer with a calculation or a good argument.

Homework Equations



Virtual particles does not obey energy (and momentum) conservation. The virtual particle never appears in the final state.

The Attempt at a Solution



I would say that the answer depends on the excitation energy of the nucleon and if the pi meson is reabsorbed. But I would spontaneous say that high - energy nucleon means energy is lower than the mass of delta (1232 MeV, mass of nucleon approx 940MeV, mass pion = 140MeV). Also I would think that the RHS is the final state, so that the pion is a real particle.

What do you guys think about that?
 
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Since the process cannot occur as an isolated process, at least one of the particles must be virtual.
 
okay, according to what argument?
 
pam said:
Since the process cannot occur as an isolated process, at least one of the particles must be virtual.

what can I check to see if it can't occur as an isolated process?

Hint?
 
malawi_glenn said:
what can I check to see if it can't occur as an isolated process?

Hint?
That's a better response, since we are not having an argument, but a discussion.
Use the invariant E^2-p^2. E^2-p^2=M^2 forthe proton.
For p plus pi, [tex](E_p+E_\pi)^2-({\vec p}_p+{\vec p}_\pi)^2<br /> =M^2+m^2+2(E_p E_\pi-{\vec p}_p\cdot{\vec p}_\pi)[/tex],
which must be greater than M^2.
 
Last edited:
but the nucleon on the LHS is excited, so there is not the same [tex]E_{\text{p}}[/tex] on the RHS.

edit: my original post (which I can't edit), the process should be (if you have not read):

[tex]N^* \rightarrow N + \pi[/tex]

the text is the same: "Assume that a high-energy nucleon is emitting a pion"
 
It's a bit frustrating to give two answers to a question and find out four days later that the wrong question was asked.
If the original N is N*, an excited nucleon, everything is different.
In that case, the particiles may be real or vilrtual.
All known N* are more massive than M_p+m_pi.
If the process is an isolated N* decaying to N and p, then all particles are real.
If N*-->N + pi is part of a more complex perturbation diagram, then one or all could be virtual. Only if a particle is in the initial or final state of an interaction is the particle real.
 

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