Conservation of relativistic momentum and energy

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SUMMARY

The discussion focuses on the decay of the K0 meson into two charged pions, specifically analyzing the momenta and speeds of the pions using relativistic physics principles. The K0 meson, at rest, decays into pions with a mass of 140 MeV/c² in a magnetic field of 2.0 T, with a radius of curvature of 34.4 cm. The participant initially attempted to calculate the velocity using classical mechanics but recognized the need for relativistic equations, particularly the relationship between momentum and velocity. The correct approach involves using the force equation F = qvB and the relativistic momentum formula to derive the velocities accurately.

PREREQUISITES
  • Understanding of relativistic momentum and energy equations
  • Familiarity with the properties of charged particles, specifically pions
  • Knowledge of magnetic fields and their effects on charged particles
  • Basic principles of particle decay and conservation laws
NEXT STEPS
  • Study the derivation and application of the relativistic momentum formula E² = p²c² + (mc²)²
  • Learn about the properties and charge of pions and other mesons
  • Explore the effects of magnetic fields on charged particles in circular motion
  • Investigate the implications of relativistic speeds and the limitations imposed by the speed of light
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Physics students, particle physicists, and educators interested in the principles of relativistic mechanics and particle decay processes.

FllOnBlckDys57
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Homework Statement



The K0 meson is an uncharged member of the particle "zoo" that decays into two charged pions according to K0 ---> π+ + π-. The pions have opposite charges as indicated, and the same mass, mπ=140MeV/c^2. Suppose that a K0 at rest decays into two pions in a bubble chamber in which a magnetic field of 2.0T is present. If the radius of curvature of the pions is 34.4cm, find (a) the momenta and speeds of the pions and (b) the mass of the K0 meson.

mπ=140MeV/c^2

r=0.344m

B=2.0T

Problem figure:

http://img208.imageshack.us/img208/171/physpr.jpg

Homework Equations



F=qv x B

F=ma

F=m(v^2/r)

E^2=p^2c^2+(mc^2)^2

p=mv/√(1-v^2/c^2)

E(K0)=E∏+ + E∏-

P(K0)=P∏+ + P∏-

The Attempt at a Solution



I feel like this problem should be started by first solving for the velocity of the particles. This could be done by combining F=qv x B and F=m(v^2/r) into m(v^2/r)=qv x B.

However, the charge (q) would still be unknown. Do pions have a standard charge? I can't seem to find it in my book. Or am I approaching this problem the wrong way?

Thanks!Update:

I am pretty sure a positive pion has a charge of 1.602E-19 C and a negative pion has an opposite charge.

I solved for the mass of the pions in kg: (140MeV/c^2)(1.783x10^-30kg/1MeV)=2.4962x10^-28 kgI then plugged these values into my equation:m(v^2/r)=qvB

(2.4962x10^-28kg)(v^2/(0.344m))=(1.602x10^-19 C)(V)(2.0T)

Solving for v, I get: v=4.42x10^8 m/s

However, this can't be right since it is faster than the speed of light. Is there some sort of relativistic equation I should be using to solve for the velocity?
 
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FllOnBlckDys57 said:
I am pretty sure a positive pion has a charge of 1.602E-19 C and a negative pion has an opposite charge.
Correct. Charge comes in a standard size.
However, this can't be right since it is faster than the speed of light. Is there some sort of relativistic equation I should be using to solve for the velocity?
It is always good to apply a sanity check to your answers, as you did.

Since this is relativistic, you should use momentum in your calculations, and then get the velocity from that. Start with [itex]F = qvB[/itex] and remember the definition of force: [itex]F = dp/dt \approx \Delta p/\Delta t[/itex].
 

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