Is the Sequence an+2=an+1+an Monotonically Increasing?

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SUMMARY

The sequence defined by the recurrence relation an+2 = an+1 + an, with initial conditions a1 = 1 and a2 = 1, is proven to be monotonically increasing. The proof utilizes the definition of a monotonically increasing sequence, which states that an+1 ≥ an for all n ∈ N. Base cases confirm that a1 ≤ a2 and a2 ≤ a3, establishing the foundation for induction. By assuming ak+1 ≥ ak, the proof demonstrates that ak+2 ≥ ak+1 holds true, confirming the sequence's monotonicity.

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analysis001
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Homework Statement


Prove that an+2=an+1+an where a1=1 and a2=1 is monotonically increasing.


Homework Equations


A sequence is monotonically increasing if an+1≥an for all n[itex]\in[/itex]N.


The Attempt at a Solution


Base cases:
a1≤a2 because 1=1.
a2≤a3 because 1<2.

Am I supposed to prove that an≤an+1 now? I'm not sure how to do that.
 
Last edited:
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analysis001 said:

Homework Statement


Prove that an+2=an+1+an where a1=1 and a2=2 is monotonically increasing.


Homework Equations


A sequence is monotonically increasing if an+1≥an for all n[itex]\in[/itex]N.

The Attempt at a Solution


Base cases:
a1≤a2 because 1=1.
a2≤a3 because 1<2.

Am I supposed to prove that an≤an+1 now? I'm not sure how to do that.
a2 ≥ a1 because 2 ≥ 1 . After all, a2 = 2 and a1 = 1 .

Now, what you need to do:
Assume that the statement is true for some k, where k ≥ 1 .
I.e.:
Assume that ak+1 ≥ ak .​
From this, show that it follows that the statement is true for k+1.
I.e.:
Show that ak+2 ≥ ak+1 .​
 

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