Is the series of c(1/2k) divergent?

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SUMMARY

The series \sum_{k=1}^{\infty} c(1/2k) where c is a positive real number is divergent. The comparison test is an effective method to demonstrate this divergence, particularly by comparing it to the series 1/n, which is known to be divergent. The Limit Comparison Test can also be applied for a more straightforward analysis. It is essential to ensure that the terms are correctly formatted in LaTeX to avoid confusion in interpretation.

PREREQUISITES
  • Understanding of series convergence and divergence
  • Familiarity with the Comparison Test and Limit Comparison Test
  • Basic knowledge of LaTeX formatting for mathematical expressions
  • Concept of divergent series, specifically 1/n series
NEXT STEPS
  • Study the Limit Comparison Test in detail
  • Explore examples of divergent series beyond 1/n
  • Practice formatting mathematical expressions in LaTeX
  • Investigate other convergence tests such as the Ratio Test and Root Test
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Mathematics students, educators, and anyone studying series convergence, particularly those focusing on advanced calculus or real analysis.

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Homework Statement



Show [tex]\sum_{k=1}^{\infty} c\k^(1\div2k, c is an element of [tex]\Re[/tex], c > 0, is divergent.<br /> <br /> <h2>Homework Equations</h2><br /> 1/n is divergent<h2>The Attempt at a Solution</h2><br /> Finding a similar series and doing comparison test, is it right?[/tex]
 
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salbakuta03 said:

Homework Statement



Show [tex]\sum_{k=1}^{\infty} c\k^(1\div2k)[/tex], c is an element of [tex]\Re[/tex], c > 0, is divergent.

Homework Equations


1/n is divergent


The Attempt at a Solution


Finding a similar series and doing comparison test, is it right?

Assuming the terms in the series are of the form c(1/2k) then the Limit Comparison Test would work too (and probably more cleanly). The series of 1/n is a good choice for this comparison. Your TeX code has the terms as "c\k^(1\div2k)" which renders without any mention to the k after the backslash. Is it displaying incorrectly? What is \k?

--Elucidus

--Elucidus
 

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