Is the Supremum/Infimum of Monotonic Functions Always at Infinity?

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The supremum and infimum of a strictly monotonic function \( f(x) \) defined on \( x \in \mathbb{R} \) occur at \( x = \infty \) with the value \( \lim_{x \uparrow \infty} f(x) \). If the function is strictly increasing or decreasing, it cannot attain a maximum or minimum value, as this would contradict the definition of strict monotonicity. In contrast, weak monotonicity allows for constant values, which can lead to maximum or minimum values. Additionally, the limit as \( x \) approaches infinity may not exist, indicating that the function could be unbounded.

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wayneckm
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Hello all,

For a monotonic increasing/decreasing function f(x) on x \in \mathbb{R}, we can only have supremum/infimum which is occurred at x = \infty with value \lim_{x\uparrow \infty}f(x) Otherwise, if it was a maximum/minimum, it would violate the assumption of monotonicity.

Am I correct on the above statement?
 
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It depends on your definition of monotonic. There are notions of strict and weak monotonicity; strict means that the function is strictly increasing/decreasing, i.e. x<y means f(x)<f(y) or f(x)>f(y).

Weak means only that x<y means f(x) \leq f(y) or f(x) \geq f(y).

If you're only looking at weak monotonicity, then you can have the function be constant after some value and achieve a maximum/minimum value. For strong monotonicity this can't occur

Also note that the limit as x goes to infinity doesn't have to exist (which means that the function is unbounded).

Obviously the same stuff applies as x goes to minus infinity also for the other bound
 
Thanks for the reply.

Ya, I forgot to state in my sense it is in strict mode.

So in summary, there does not exist maximum/minimum for a strictly increasing/decreasing function in the case of function f on \mathbb{R}?
 
That's right.
 

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