Is the Work Function of Graphene Equal to the Binding Energy?

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The work function of graphene is assumed to be 4.5 eV, but it does not equal the binding energy E_B as stated on Wikipedia; rather, it is related to it. In the context of the graph, E in E−E_F represents energy at a specific point in the Brillouin zone, which is not necessarily the Fermi level. The Fermi level is indeed located at the point E=E_F above K in the graph. Additionally, the second Brillouin zone K-point corresponds to the point labeled K in the left plot. Understanding these distinctions is crucial for analyzing the electronic properties of graphene.
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Homework Statement
See the attached image.
Relevant Equations
The theory section on ARPES on Wikipedia: https://en.wikipedia.org/wiki/Angle-resolved_photoemission_spectroscopy#Theory
Consider the attached screenshot. The work function of graphene is assumed to be 4.5 eV.

1. Does the work function correspond to the binding energy ##E_B## as given on Wikipedia? What is ##E## in ##E−E_F## in the graph on the right?
2. "...the Fermi level at the K-point..."; is this the point ##E=E_F## above K in the graph on the right?
3. "...the second Brillouin zone K-point..."; which point is this in the two pictures?
Screen Shot 2021-03-11 at 14.50.51.png
 
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1. No, the work function does not correspond to the binding energy ##E_B## as given on Wikipedia. The work function is related to the binding energy, but is not equal to it. ##E## in ##E − E_F## in the graph on the right is the energy at a particular point in the Brillouin zone, which is not necessarily the Fermi level.2. Yes, this is the point ##E = E_F## above K in the graph on the right.3. The second Brillouin zone K-point is the point labeled K in the plot on the left.
 
I want to find the solution to the integral ##\theta = \int_0^{\theta}\frac{du}{\sqrt{(c-u^2 +2u^3)}}## I can see that ##\frac{d^2u}{d\theta^2} = A +Bu+Cu^2## is a Weierstrass elliptic function, which can be generated from ##\Large(\normalsize\frac{du}{d\theta}\Large)\normalsize^2 = c-u^2 +2u^3## (A = 0, B=-1, C=3) So does this make my integral an elliptic integral? I haven't been able to find a table of integrals anywhere which contains an integral of this form so I'm a bit stuck. TerryW

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