# Is there a closed form for this?

1. Jan 25, 2016

### S_David

Hi,

I have this integral:

$$\int_0^∞ \ln(1+x)\,e^{-x}\,dx$$

Is there any closed form expression for it?

Thanks

2. Jan 25, 2016

### Samy_A

Integration by parts shows that the result contains the Exponential integral function Ei evaluated in -1.
Depends of whether you call that a closed form expression.

3. Jan 25, 2016

### S_David

No, I need it in basic functions that have simple derivatives.

4. Jan 25, 2016

### Samy_A

Well, the derivative of Ei is $\frac{e^x}{x}$.

5. Jan 25, 2016

### S_David

OK, thanks. Does $e^{-x}$ goes to zero faster than $\ln(1+x)$ goes to infility as $x→∞$?

6. Jan 25, 2016

### Samy_A

Yes. If not your integral wouldn't give a finite result. $e^{-x}$ also goes to zero faster than any polynomial goes to infinity as $x→+∞$.

Last edited: Jan 25, 2016
7. Jan 25, 2016

### S_David

OK. I worked the analysis, and it won't work with me. I have something like this

$$\int_0^∞ \ln(1+s\,x)\,e^{-x}\,dx$$

and I need to find

$$\frac{\partial}{\partial s}\int_0^∞ \ln(1+s\,x)\,e^{-x}\,dx$$

from which I need to find $s$. The integral is a complicated function of the argument $s$.

8. Jan 25, 2016

### Krylov

It is not that I found your comments unhelpful, but I just wanted to know enough to do the analysis, without going into the details. If I follow the same logic as the paper I attached there, and applied it to my problem here, I will have the p.d.f of $x$ appearing in the derivative. How to handle this when I need some numerical results?