Undergrad Is There a Faster Way to Prove Smoothness on Manifolds?

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Proving that a function between smooth manifolds is smooth typically involves checking the smoothness of its coordinate representation. The discussion highlights the desire for faster methods, such as leveraging the inverse function theorem or other established theorems. One participant notes the complexity of explicitly constructing bijections and verifying smoothness, expressing a wish for simpler approaches. The conversation acknowledges that understanding these concepts may take time, especially for those new to the study of smooth manifolds. Overall, the thread emphasizes the challenge of proving smoothness and the potential for using theorems to simplify the process.
JonnyG
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So if ##M, N## are smooth manifolds then ##F: M \rightarrow N## is smooth if given ##p \in M##, there is a smooth chart ##(U, \phi)## containing ##p## and a smooth chart ##(V, \psi)## containing ##F(p)## such that ##\psi \circ F \circ \phi^{-1}: \phi(U \cap F^{-1}(V)) \rightarrow \mathbb{R}^n## is smooth.

If I wanted to prove that a given function was smooth, are there any faster ways other than showing that its coordinate representation is smooth? For example, I just did a question where I had to show that ##T(M \times N)## is diffeomorphic to ##T(M) \times T(N)##. I had to explicitly construct a bijection between the two manifolds then show that the coordinate representations of ##F## and ##F^{-1}## were smooth. This was a big pain. I wish there was a theorem I could have appealed to instead.
 
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Inverse function theorem?
Sections of the tangent bundle?

It really depends on what you have seen already.
 
Thanks, micromass. I haven't learned the inverse function theorem on manifolds yet, but I suppose it's the usual inverse function theorem applied to the coordinate representation of the map I'm interested in. I am still early in my study of smooth manifolds - I'll be more patient.
 

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