Is There a Formula for These Summation Problems?

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Homework Help Overview

The discussion revolves around summation problems, specifically the search for formulas related to harmonic sums and the summation of integers. Participants are exploring the representation and calculation of these sums, as well as the challenges in finding closed-form expressions.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants are attempting to identify formulas for specific summations, including harmonic sums and the sum of integers. Questions arise regarding the notation used and the validity of the expressions presented. Some participants suggest straightforward addition for small sums while others express confusion over the correct formulation.

Discussion Status

The discussion is active, with participants sharing their thoughts on the nature of the sums and questioning the correctness of the provided formulas. There is an exploration of different interpretations of the summation notation, and some guidance is offered regarding the addition of fractions and the characteristics of harmonic sums.

Contextual Notes

Participants note the complexity of summations as the number of terms increases, and there is mention of issues with LaTeX formatting in the original posts. The conversation reflects a mix of attempts to clarify definitions and the challenges of finding established formulas in algebra and calculus literature.

mech-eng
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Homework Statement
I wonder if there is a formula for this summation: ##\sum_{n=1}^5= \frac 1n##
Relevant Equations
I know some formulas for summations but I don't know any formula for this case

##\sum_{k=1}^n=\frac{n({n+1})}2##
I look though some algebra and calculus books but I didn't see any formula for this some, and I am stuck here. I can just represent it in a notation but I cannot think a formulation to obtain the result.

##\sum_{k=1}^{n=5}=\frac {n!}{n!k} ##

Thank you.
 
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mech-eng said:
I look though some algebra and calculus books but I didn't see any formula for this some, and I am stuck here. I can just represent it in a notation but I cannot think a formulation to obtain the result.

##\sum_{k=1}^{n=5}=\frac{n!}{n!k} ##

Thank you.

Since you have a simple sum of 5 numbers, what is preventing you from just doing the addition? Admittedly, you need to find a common denominator, but that should not be too hard.

In general, there is no known "closed-form" formula for the so-called harmonic number, defined as
$$H(n) = \sum_{k=1}^n \frac 1 k $$
However, there are simple approximate formulas whose performance becomes better as ##n## becomes larger.
 
Ray Vickson said:
Since you have a simple sum of 5 numbers, what is preventing you from just doing the addition?

It was just an example. Sum might be 20 or 30 numbers. Yes with just 5 numbers it is very easy and the common denominator could be 5!. Is that called an ##\textrm {harmonic sum}##?

Meanwhile would you also explain why my fraction line does not appear in my post the first post? What is wrong with my latex code?

Thanks
 
Maybe a way of double-checking if the formula is right is using the fact that it is known that the sum will never be an integer.
 
mech-eng said:
I wonder if there is a formula for this summation: ##\sum_{n=1}^5= \frac 1n##
I know some formulas for summations but I don't know any formula for this case

##\sum_{k=1}^n=\frac{n({n+1})}2##
I look though some algebra and calculus books but I didn't see any formula for this some, and I am stuck here. I can just represent it in a notation but I cannot think a formulation to obtain the result.

##\sum_{k=1}^{n=5}=\frac {n!}{n!k} ##
None of your equations makes any sense, since you aren't including that thing being summed.
It's as if you asked someone to evaluate this integral: ##\int_1^5##.

Is the first summation supposed to be ##\sum_{n=1}^5 \frac 1n##? If so, I don't know of any formula, but it's pretty easy to add the five fractions.

For your second equation, it looks like what you meant is ##\sum_{k=1}^n k =\frac{n({n+1})}2##, the sum of the first k positive integers.
 

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