# I Is there a psi ontic Copenhagen interpretation?

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1. Feb 10, 2017

### Nickyv2423

Is there a psi ontic version of the Copenhagen interpretation ( where the wave function is regarded real)? Can the wave function be real in Copenhagen interpretation?

2. Feb 10, 2017

### atyy

Yes, the wave function can be real in Copenhagen. Copenhagen is ambivalent about the reality of psi.

3. Feb 11, 2017

### martinbn

What does it mean for the wave function to be real?

4. Feb 13, 2017

### Demystifier

I think the von Neumann collapse interpretation can be considered as an ontic version of Copenhagen.

5. Feb 13, 2017

### Demystifier

It means ontic. If you ask what ontic means in mathematical terms, then I have two answers.

One is the PBR criterion: https://arxiv.org/abs/1111.3328v3

The other is "real" roughly in the sense in which numbers are real according to mathematical Platonists. For instance, is continuum hypothesis true in reality? The question makes sense for Platonists, despite the fact that it is undecidable by ZF axioms.

Last edited: Feb 13, 2017
6. Feb 13, 2017

### Staff: Mentor

I'm not sure I understand how this criterion is supposed to work. Their criterion basically seems to be that something is a "physical property" if for any collection of probability distributions $L$ corresponding to that property, the distributions corresponding to different labels $L$, $L'$ are disjoint (Fig. 1 in the paper and accompanying discussion). But, using their example of a classical point particle in one dimension, position would seem to be a physical property but there are certainly collections of probability distributions corresponding to position that are not disjoint (for example, any collection of Gaussians centered on different points). Does that mean position of a classical particle is not a physical property?

7. Feb 14, 2017

### Demystifier

The PBR criterion is not concerned with the question whether any of the observables (position, momentum, spin, ...) is ontic. They only consider the question whether the wave function (which is not an observable) is ontic. And their conclusion is that it is. But note that conclusion is based on the assumption that there is something which is ontic. So if there is something ontic at all (which a priori may be something different from wave function, for instance it can be Bohmian particle positions), then wave function is ontic too.

8. Feb 14, 2017

### Staff: Mentor

The paper uses the term "physical property", and I'm trying to understand what it means by that. In the classical case, it certainly seems to me that position should be a physical property--indeed, in the usual formulation of classical mechanics, position is part of the "underlying state" that the paper labels $\lambda$, which is assumed to be ontic. Yet position does not seem to meet the paper's criterion for something ontic; so I'm confused about what the criterion is supposed to mean. If it doesn't mean that position in classical mechanics is ontic, then I don't see why I should care about their criterion since it doesn't match anything that seems useful to me. But if it is supposed to mean that position in classical mechanics is ontic, then their actual formulation doesn't seem to match that.

9. Feb 14, 2017

### atyy

I think it is something like this:
For a single particle, the state is (x,p). If you know x=a with certainty, then the probability distribution u(x=a,p) is disjoint from the distribution u(x=b,p) if you know x=b with certainty. [Sorry for the terrible notation.]

10. Feb 15, 2017

### Demystifier

Position is ontic in classical mechanics, and the authors of the paper take it for granted. But that's not what they are concerned about. They want to determine whether something like probability amplitude can be ontic. So they devise a criterion which can be applied to probability amplitudes. A particle position is not a probability amplitude, so it's not so simple to apply the criterion to particle positions. A probability amplitude associated with an ontic position $X$ is something like
$$\psi(x)=\sqrt{\delta(x-X)}$$
If you wander what is the square root of the $\delta$-function, see
https://www.physicsforums.com/threa...luding-dirac-delta.873711/page-2#post-5487662
https://www.physicsforums.com/threa...luding-dirac-delta.873711/page-2#post-5488516

11. Feb 15, 2017

### Staff: Mentor

But what if you don't? That's the case the paper appears to be discussing.

But uncertain knowledge of a particle position should be--more precisely, it should be a probability distribution, and the paper's reasoning should apply to it.

12. Feb 15, 2017

### atyy

In their example with energy, one knows the energy exactly.

Actually, I think the original paper introducing this definition gave a clearer motivation, might be worth looking at it: https://arxiv.org/abs/0706.2661 (Fig 2, not Fig 1).

13. Feb 15, 2017

### Staff: Mentor

I'll take a look.