Is There an Algebraic Solution for 36=X^X?

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SUMMARY

The equation 36=X^X can be solved algebraically using the Lambert-W Function. The function f(x) = x^x - 36 is continuous, and by applying the half interval method implemented in the ARIBAS_W workbench, the zero of f(x) can be approximated between 3.1 and 3.2, yielding a solution of approximately 3.13564239388907368. This method provides a definitive approach to finding the solution rather than relying solely on graphical methods.

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  • Understanding of the Lambert-W Function
  • Familiarity with continuous functions and their properties
  • Knowledge of numerical methods, specifically the half interval method
  • Experience with the ARIBAS_W workbench tool
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  • Research the properties and applications of the Lambert-W Function
  • Learn about continuous functions and their behavior
  • Study numerical methods for root-finding, focusing on the half interval method
  • Explore the features and capabilities of the ARIBAS_W workbench
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Mathematicians, students studying algebraic equations, and anyone interested in advanced numerical methods for solving equations.

Freespader
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I came up with an idea for an equation, which follows: 36=X^X. I tried solving it, but I couldn't. I found the graphically (3.15, if I recall correctly), but I want to know if there's a way to solve it algebraically.
 
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Freespader said:
… I want to know if there's a way to solve it algebraically.

nope! :redface:
 
Actually, you can, but you need to use the Lambert-W Function.
 
Let f(x):=x^{x} - 36, (f(x) is continuous, f(3.1) < 0, f(3.2) > 0) we can apply

the 'half intervall' function I implemented in my ARIBAS_W workbench, to find the zero of f(x)

in the intervall (3.1,3.2) as: 3.13564239388907368
 

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