Is this 'e' interpretation correct?

  1. Considering e is the limit->+oo of (1+1/n)^n, then is e "what you get if you wait for the least gain, by waiting for the most amount of time"? Something like "e is the patience number".
     
  2. jcsd
  3. arildno

    arildno 12,015
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    Hmm..No.
     
  4. No explanation?
     
  5. Mentallic

    Mentallic 3,699
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    Is this in regards to compound interest returns?
     
  6. arildno

    arildno 12,015
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    You might wish to look at, for example, the actual limit of, for example, (1+1/(3n))^(2n)
    which, for every particular choice of "n" will have a less gain waited for for an even greater period of time than the one you happende to pick.
     
  7. HallsofIvy

    HallsofIvy 40,504
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    What explanation could be given when you haven't said what you mean by "gain" or "waiting".
     
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