Is this function uniformly continuous?

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SUMMARY

The discussion centers on the uniform continuity of the extension function g: X->Y, derived from a uniformly continuous function f: A->Y, where A is a dense subset of the metric space X and Y is a complete metric space. It is established that under these conditions, the extension g is uniformly continuous. The key steps involve proving the existence and uniqueness of the extension g, which adheres to the properties of uniform continuity based on the density of A in X.

PREREQUISITES
  • Understanding of metric spaces and their properties
  • Knowledge of uniform continuity and its implications
  • Familiarity with dense subsets in topology
  • Concept of function extension in mathematical analysis
NEXT STEPS
  • Study the properties of uniformly continuous functions in metric spaces
  • Learn about the construction of function extensions in analysis
  • Explore the concept of dense subsets and their significance in topology
  • Investigate the implications of completeness in metric spaces
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Mathematics students, particularly those studying real analysis and topology, as well as educators looking to deepen their understanding of uniform continuity and function extensions.

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Homework Statement


we have 2 metric spaces (X, d) and (Y, d')

given:
1) A is a dense subset of X
2) Y is complete
3) there is a uniformly continuous function f: A->Y

let g: X->Y be the extension of f
that is, g(x)=f(x), for all x in A

is g uniformly continuous?

Homework Equations


The Attempt at a Solution



not sure where to start...
 
Last edited:
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You could start by proving that such an extension exists and is unique. How would you define g?
 

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