Is this grignard preparation mechanism correct?

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SUMMARY

The discussion centers on the Grignard preparation mechanism, specifically the role of magnesium in transferring an electron to the C-X bond, resulting in a magnesium radical and a carbon radical. The halogen atom departs with two electrons, forming a negatively charged bromide ion that bonds ionically with the magnesium radical. The participants confirm the accuracy of the mechanism while debating the representation of formal charges in the reaction. The mechanism aligns with established literature, including the referenced site from the University of Texas.

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Horseb0x
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[PLAIN]http://img443.imageshack.us/img443/6488/mechanisma1.png
The magnesium transfers an electron to the C-X bond, yielding a Mg radical. The halogen atom leaves with 2 electrons from the bond and the carbon is converted into a radical. The negatively charged bromide ion forms an ionic bond with the positively charged Mg radical. The single electrons of the carbon radical and Mg radical are used to form a new covalent bond.

Is this correct? Also is my wording and mechanism drawing adequate?
 
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Horseb0x said:
[PLAIN]http://img443.imageshack.us/img443/6488/mechanisma1.png
The magnesium transfers an electron to the C-X bond, yielding a Mg radical. The halogen atom leaves with 2 electrons from the bond and the carbon is converted into a radical. The negatively charged bromide ion forms an ionic bond with the positively charged Mg radical. The single electrons of the carbon radical and Mg radical are used to form a new covalent bond.
Is this correct? Also is my wording and mechanism drawing adequate?

I don't agree with the formal negative charge you have shown. Remember that it gained 1 electron from Mg and lost one to Br.
 
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