Is this grignard preparation mechanism correct?

Horseb0x
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[PLAIN]http://img443.imageshack.us/img443/6488/mechanisma1.png
The magnesium transfers an electron to the C-X bond, yielding a Mg radical. The halogen atom leaves with 2 electrons from the bond and the carbon is converted into a radical. The negatively charged bromide ion forms an ionic bond with the positively charged Mg radical. The single electrons of the carbon radical and Mg radical are used to form a new covalent bond.

Is this correct? Also is my wording and mechanism drawing adequate?
 
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Horseb0x said:
[PLAIN]http://img443.imageshack.us/img443/6488/mechanisma1.png
The magnesium transfers an electron to the C-X bond, yielding a Mg radical. The halogen atom leaves with 2 electrons from the bond and the carbon is converted into a radical. The negatively charged bromide ion forms an ionic bond with the positively charged Mg radical. The single electrons of the carbon radical and Mg radical are used to form a new covalent bond.
Is this correct? Also is my wording and mechanism drawing adequate?

I don't agree with the formal negative charge you have shown. Remember that it gained 1 electron from Mg and lost one to Br.
 
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