Is This Integral a Candidate for Asymptotic Analysis?

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SUMMARY

The integral of the form \(\int^{\infty}_{-\infty}\frac{x(\omega)}{\sigma^{2} + \omega^{2}}d\omega\) is indeed a candidate for asymptotic analysis, particularly as \(\omega\) approaches positive or negative infinity where the integrand approaches zero. However, the convergence behavior is slower than that of integrals with decaying exponentials, which complicates the analysis. The discussion emphasizes the need for a specific function \(x(\omega)\) to derive a more general result, suggesting that contour integration methods may be applicable for specific cases.

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thrillhouse86
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Hey:

I have an integral of the form:
[tex] \int^{\infty}_{-\infty}\frac{x(\omega)}{\sigma^{2} + \omega^{2}}d\omega[/tex]

I'm wondering if this integral is a candidate for asymptotic analysis. My rationale is that as omega increases to either positive infinity or negative infinity, the function being integrated will go to zero. The problem is that every integral I've seen put into an Asymptotic form has had a decaying exponential (which I guess is a much quicker convergence to zero than 1/w^2).

Also - I can guarantee that any f(w) considered is square integrable, and sigma is real

I realize that I can probably just evaluate the integral using contour methods if I have a specific f(w), but I am trying to derive the most general result I can.

I guesss my question is:
1. Is this a candidate for asymptotic analysis
2. If so can someone point me in the direction of obtaining the asymptotic form ?

Thanks
 
Last edited:
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Without any knowledge about ##x(\omega)## the integral could be anything.
 

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