Is This Integration Calculation Correct?

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SUMMARY

The forum discussion centers on the correctness of an integration calculation involving the expression C(S,V,t) = 1 - (1/2π) * exp[-λ(k0)*t](u(k0,V)/k0² - i*k0) + ∫(from -∞ to +∞) S * exp[-0.5 * kr² * λ''(k0) * t] dkr. The user questions the evaluation of the integral, suggesting it should yield zero at both limits, but the provided solution indicates otherwise. The discussion highlights the complexity of integrating functions with squared terms in the exponent, referencing the Gaussian integral ∫(from -∞ to +∞) e^{-x²}dx = √π as a relevant example.

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Bazman
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Hi,

i've seen a textbook where the integration inthe following expression is performed:


C(S,V,t) = 1-(1/2pi)*exp[-lambda(k0)*t](u(k0,V)/k0^2-i*k0)
+ infin
*S exp[-.5*kr^2*lambda''(k0)*t]dkr
- infin

where kr is k subscript r and k0 is ksubscript 0
i = complex number
lamda'' =2nd derivative of lambda

giving


=1-(u(k0,V)/(k0^2-i*k0)*(1/(2pi*lamda''(k0)*t)^.5)*exp[-lambda(k0)*t]


to me the integral

+ infin
*S exp[-.5kr^2*lambda''(k0)t]dkr
- infin

should give exp[-.5kr^2lambda''(k0)*t]/(-kr*lambda''(k0)*t)

evaluated at + and - infin and in both cases should go to zero but from the solution above this is clearly incorrect

please let me know where I am going wrong
 
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[tex]\int e^{a k_r}dr= \frac{1}{a}e^{ak_r}[/tex]
but you have kr2. That square in the exponential means that the anti-derivative cannot be written as an elementary function.
Are you familiar with
[tex]\int_{-\infty}^\infty e^{-x^2}dx= \sqrt{\pi}[/tex]?
 

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