(adsbygoogle = window.adsbygoogle || []).push({}); 1. The problem statement, all variables and given/known data

Find the general solution of

y' + (2/x)y = 3/(x^2)

3. The attempt at a solution

xy' + 2y = 3/x

d/dx (x * 2y) = 3/x

integrating both sides (using product rule for LHS) I end up with

y= (3lnx + C)/2x

Then I am supposed to find the solution for which y(2) = -1 so I subbed that into the above and got c = -4/3 - ln2

So then I can say that y = 3lnx/(2x) - 4/3 -ln2

Hope thats right!

Thanks guys!

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# Homework Help: Is this the correct answer for a partial differentiation question?

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