- #1
laura_a
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Homework Statement
Find the general solution of
y' + (2/x)y = 3/(x^2)
The Attempt at a Solution
xy' + 2y = 3/x
d/dx (x * 2y) = 3/x
integrating both sides (using product rule for LHS) I end up with
y= (3lnx + C)/2x
Then I am supposed to find the solution for which y(2) = -1 so I subbed that into the above and got c = -4/3 - ln2
So then I can say that y = 3lnx/(2x) - 4/3 -ln2
Hope that's right!
Thanks guys!