Is this the correct formula that im using for this question?

  • Thread starter Thread starter ImsoFly
  • Start date Start date
  • Tags Tags
    Formula
Click For Summary
SUMMARY

The discussion centers on calculating the distance traveled by a two-stage toy rocket that accelerates from 12 m/s to 40 m/s over 5.0 seconds. The correct approach involves using the kinematic equation d = (v_i + v_f)/2 * t, where v_i is the initial velocity (12 m/s) and v_f is the final velocity (40 m/s). Participants clarify that the acceleration should be calculated first, but emphasize that the primary goal is to find the distance, not the time. The kinematic equations are essential tools for solving such problems involving constant acceleration.

PREREQUISITES
  • Understanding of kinematic equations
  • Basic knowledge of acceleration and velocity
  • Ability to manipulate algebraic formulas
  • Familiarity with physics concepts related to motion
NEXT STEPS
  • Study the derivation and application of kinematic equations
  • Learn how to calculate acceleration using the formula a = Δv / Δt
  • Explore examples of motion problems involving constant acceleration
  • Review physics resources on velocity and distance calculations
USEFUL FOR

Students studying physics, educators teaching motion concepts, and anyone seeking to understand kinematic equations and their applications in real-world scenarios.

ImsoFly
Messages
48
Reaction score
0
1. Homework Statement
hi this is the problem: the burning of the second stage of a two stage toy rocket takes the rocket from 12 m/s to 40 m/s in 5.0s. How far does the rocket during this time?


2. Homework Equations
would i use delta t= delta v/a ? would the given info be.. delta v1= 17 m/s, delta v2=40m/s and delta t=5.0s... if this isn't the correct formula please correct me. thank u all!:smile:
 
Physics news on Phys.org
distance = (1/2)*a*t^2 + vi*t

where a = delta v / delta t

and vi is the initial velocity (12 m/s)
 
misterme09 said:
distance = (1/2)*a*t^2 + vi*t

where a = delta v / delta t

and vi is the initial velocity (12 m/s)
but the question asks for time
 
ImsoFly said:
but the question asks for time

No it doesnt.. it asks for distance! Firstly, work out the acceleration using your equation, then plug this along with initial velocity and time into the equation for distance given in post #2.
 
cristo said:
No it doesnt.. it asks for distance! Firstly, work out the acceleration using your equation, then plug this along with initial velocity and time into the equation for distance given in post #2.
what do you mean by working out the acceleration?
 
ImsoFly said:
what do you mean by working out the acceleration?

sorry, you'll just be going round in circles by doing that! you can use another of the "kinematic equations", namely d=\frac{v_i+v_f}{2}\cdot t.

Here's a link to the kinematic equations http://www.glenbrook.k12.il.us/GBSSCI/PHYS/Class/1DKin/U1L6a.html . These equations are normally the tools you need for questions involving a constant acceleration.
 
Last edited by a moderator:
cristo said:
sorry, you'll just be going round in circles by doing that! you can use another of the "kinematic equations", namely d=\frac{v_i+v_f}{2}\cdot t.

Here's a link to the kinematic equations http://www.glenbrook.k12.il.us/GBSSCI/PHYS/Class/1DKin/U1L6a.html . These equations are normally the tools you need for questions involving a constant acceleration.

kk, thanks a bunch:-p
 
Last edited by a moderator:

Similar threads

  • · Replies 2 ·
Replies
2
Views
3K
  • · Replies 5 ·
Replies
5
Views
3K
Replies
10
Views
2K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 6 ·
Replies
6
Views
2K
  • · Replies 1 ·
Replies
1
Views
1K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 1 ·
Replies
1
Views
1K
  • · Replies 6 ·
Replies
6
Views
3K
  • · Replies 1 ·
Replies
1
Views
2K