Is U Invariant under T if PUTPU = TPU?

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SUMMARY

U is invariant under the linear transformation T if and only if the equation PUTPU = TPU holds true. In this context, PU represents the projection operator that projects vectors onto the subspace U. The proof demonstrates that if U is invariant under T, then applying the projection operator PU after T results in the same output as applying T directly to a vector in U. This establishes the equivalence of the two expressions, confirming the condition for invariance.

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Homework Statement


Suppose T ∈ L(V) and U is a subspace of V. Prove that U is
invariant under T if and only if PUTPU = TPU.

Homework Equations


The Attempt at a Solution


Consider u[tex]\in[/tex]U. Now let U be invariant under T. Now let PU project
v to U so that PU(v)=u. Therefore TPU(v)=T(u). Now
since T(u) is[tex]\in[/tex]U, PU should project T(u) back to U and
by the definition of P^2=P, PU must be an identity operator since T(u) is in U,
the space PU projects T(u) to, so PUTPU(v)=PUT(u)=T(u)
which is equivalent to TPUv since TPUv =T(u) thus PUTPU=TPU.
 
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would like to know whether or not its right or wrong, thank you!:smile:
 

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