Is Vertical Compression Correctly Applied in This Function Transformation?

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SUMMARY

The discussion centers on the application of vertical compression in the function transformation of f(x) = 2(x^2) - 4. The correct transformation results in g(x) = (x^2) - 2 after applying a vertical compression by a factor of 1/2. The initial confusion arises from a misunderstanding of how vertical changes affect the output of the function. The solution confirms that the vertical compression modifies the entire output value, leading to the new equation.

PREREQUISITES
  • Understanding of function transformations
  • Familiarity with vertical compression and its mathematical implications
  • Knowledge of the distributive property in algebra
  • Basic skills in manipulating quadratic functions
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  • Review the principles of function transformations in algebra
  • Study vertical and horizontal compressions and their effects on graphs
  • Practice applying the distributive property in various mathematical contexts
  • Explore quadratic functions and their transformations in detail
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Students learning algebra, educators teaching function transformations, and anyone seeking to clarify concepts related to vertical compression in quadratic equations.

dragon513
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Q. Given f(x)=2(x^2)-4 , determine the new equation g(x) after a vertical compression by a factor of 1/2.

The answer provided by the book is g(X) = (x^2)-2, but shouldn't it be g(x) = (x^2)-4 ?

Help will be much appreciated.

Regards,

Adam
 
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dragon513 said:
Q. Given f(x)=2(x^2)-4 , determine the new equation g(x) after a vertical compression by a factor of 1/2.

The answer provided by the book is g(X) = (x^2)-2, but shouldn't it be g(x) = (x^2)-4 ?

Help will be much appreciated.

Regards,

Adam
No, the book's solution is correct. Horizontal changes are changes in x, vertical changes are changes in y. Since this is a vertical compression by 1/2, first calculate y= 2x2- 4, the calculate (1/2)y= (1/2)(2x2- 4)= x2- 2 (becareful to use the "distributive law"- multiply both parts by 1/2). The new y is y= x2- 2.
 

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