Is voltage drop different in parallel circuits?

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Homework Help Overview

The discussion revolves around the concept of voltage drop in parallel circuits, with participants exploring their understanding of how voltage behaves in such configurations compared to series circuits.

Discussion Character

  • Conceptual clarification, Assumption checking

Approaches and Questions Raised

  • Participants express confusion regarding the nature of voltage drop in parallel circuits, questioning whether it is the same as the power supply voltage or varies across components. There are attempts to clarify the original poster's statements and to understand the implications of breaking the circuit.

Discussion Status

The discussion is ongoing, with participants seeking clarification on the original poster's understanding and exploring different interpretations of voltage drop in parallel circuits. Some guidance has been offered, but no consensus has been reached on the correct understanding of the concept.

Contextual Notes

There appears to be some uncertainty regarding the definitions and comparisons being made between parallel and series circuits, as well as the implications of circuit modifications on current flow.

TonyG247
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I was under the impression that voltage drop was the same in parallel which would make it the power supply, but apparently not? Any insight would help. I know this isn't a hard a question, I'm just horrible at physics.
 
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TonyG247 said:
I was under the impression that voltage drop was the same in parallel which would make it the power supply, but apparently not?

Can you reword this? I think I know what you're saying, but I don't think you're saying it very well.

The same in parallel compared to what? To series? No, but I don't think this is what you meant. I think you meant it's the same as the power supply voltage. Is this correct?
 
Student100 said:
Can you reword this? I think I know what you're saying, but I don't think you're saying it very well.

The same in parallel compared to what? To series? No, but I don't think this is what you meant. I think you meant it's the same as the power supply voltage. Is this correct?

My apologies. Yes, the same as the power supply. And if that isn't the case, at least the same in each of the resistors. But the answer doesn't seem to be correct? I'm lost on how I should go about calculating the voltage drop with the provided information.
 
Say I pulled out what I can only assume is an ammeter, breaking the circuit there? Would current still flow?
 
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